import math EPSILON = 1.0e-14 def square_root(number): approximation = 1 previous = 0 iterations = 0 while ((absolute value of (approximation * approximation minus number) is greater than EPSILON) and previous != approximation): previous = approximation approximation = 0.5 * (approximation + number / approximation) iterations += 1 return (approximation, iterations)

One remarkably simple formula for calculating the value of p is the so-called Madhava-Leibniz series: p4 =わ 1-ひく13+たす15-ひく17+たす19-.... Consider the recursive function below to calculate the first n terms of this formula: double computePI(int n) { if (n <= 1) { return 1.0;} int oddnum = 2 * n - 1; if ((n % 2) == 0 { } return -1.0 oddnum + computePI(n − 1); } else { } return 1.0 / oddnum + computePI (n - 1); Which statements about the run-time performance of this function are true? 1.Each time this function is called it will invoke at least two more recursive calls II.The number of recursive calls this function will make is approximately equal to the value of the parameter variable n III.Not counting overhead, this function will be about as efficient as an iterative implementation of the same formula

25 def iceCreamOrder (cost flavor # vanilla 26 27 28 29 30 31 32 def run(): 33 34 35 36 37 38 =わ 6): input ("What flavor would you like?\n") return "The flavor print(iceCreamOrder ())] " + flavor + will cost printStatement() print (returnValues()) print (parameters (1,4)) print (parameters (5,7)) print (iceCreamOrder()) return #Do NOT change anything in this line! + str(cost) + " dollars."

write a code in java (using recursion)

Can someone help me answer this question?

The following recursive method get Number Equal searches the array x of 'n integers for occurrences of the integer val. It returns the number of integers in x that are equal to val. For example, if x contains the 9 integers 1, 2, 4, 4, 5, 6, 7, 8, and 9, then getNumberEqual(x, 9, 4) returns the value 2 because 4 occurs twice in x. public static int getNumberEqual(int x[], int n, int val) { if (n< 0) ( return 0; } else { if (x[n-1) == val) { return getNumberEqual(x, n-1, val) +1; } else { return getNumber Equal(x, n-1, val); } // end if ) // end if } // end get Number Equal Demonstrate that this method is recursive by listing the criteria of a recursive solution and stating how the method meets each criterion.

Fix the code below so that there is a function that calculate the height of the triangle. package recursion; import javax.swing.*;import java.awt.*; /** * Draw a Sierpinski Triangle of a given order on a JPanel. * * */public class SierpinskiPanel extends JPanel { private static final int WIDTH = 810; private static final int HEIGHT = 830; private int order; /** * Construct a new SierpinskiPanel. */ public SierpinskiPanel(int order) { this.order = order; this.setMinimumSize(new Dimension(WIDTH, HEIGHT)); this.setMaximumSize(new Dimension(WIDTH, HEIGHT)); this.setPreferredSize(new Dimension(WIDTH, HEIGHT)); } public static double height(double size) { double h = (size * Math.sqrt(3)) / 2.0; return h; } /** * Draw an inverted triangle at the specified location on this JPanel. * * @param x the x coordinate of the upper left corner of the triangle * @param y the y...

The following recursive method called z is created. This method accepts two parameters: A string s, and an integer index The code in the method is: if (index == s.length()) return ""; <------ base case if(index % 2 == 0) return ""+ s.charAt(index) + z(s,index+1); <---- recursive call else return z(s,index+1); <----- recursive call What would be the output with the call: z("javajavajava",0);

Analyze errorIf (x < 100) && (x> 10)System.out.println("x" is between 10 and 100");

I need the code from start to end with no errors and the explanation for the code ObjectivesJava refresher (including file I/O)Use recursionDescriptionFor this project, you get to write a maze solver. A maze is a two dimensional array of chars. Walls are represented as '#'s and ' ' are empty squares. The maze entrance is always in the first row, second column (and will always be an empty square). There will be zero or more exits along the outside perimeter. To be considered an exit, it must be reachable from the entrance. The entrance is not an exit.Here are some example mazes:mazeA7 9# # ###### # # ## # # #### # ## ##### ## ########## RequirementsWrite a MazeSolver class in Java. This program needs to prompt the user for a maze filename and then explore the maze. Display how many exits were found and the positions (not indices) of the valid exits. Your program can display the valid exits found in any order. See the examples below for exact output requirements. Also, record...

Write a program called Recursive_fibonacci.java that implements a recursive function for computing the nth term of a Fibonacci Sequence. In the main method of your program accept the value of n from the user as a command-line argument and then call your function named Fibonacci with this value. The output should look exactly like what is pictured below.