Implement the following pseudocode in assembly language. Use short-circuit evaluationand assume that X is a 32-bit variable.if( ebx > ecx ) OR ( ebx > val1 )X = 1elseX = 2

NAND2TETRIS HARDWARE SIMULATOR (HARDWARE DESCRIPTION LANGUAGE (HDL)) implement simplified Z80 Arithmetic and Logic Unit using the skeleton program below , also using the predifined gates which are in the images attached CHIP ALUcore { IN a[4], b[4], carryIn, sums, ands, xors, ors; OUT out[4], carryOut; PARTS: }

please give a step by step implementation of this using only operators in the nand2tetris hack assembly language

2. Write the assembly code for the following high-level pseudo code: if ((a>=b) AND (b==c)) OR (a<=c) then a =b+c else a = b -c

For the following C statement, write a minimal sequence of MIPS assembly instructions that does the identical operation. int arr[] = {0x11,0x22, 0x33, Øx44, Øx55}; arr[2] = arr[0] + 3;

Please can you convert this part of a c program to pep 9 assembly language void findLog ( int *result, int num, int b ) { int k; num--; *result = 0; while (num > 0) { *result = *result + 1; num = divide(num, b); } // end while } // end of findLog( )

Implement the following expression in masm x86 assembly language: ECX = –(val3 - val1) + (-val4 + val2) + 3 a screenshot is needed - Assume that val1 is 16-bit variable, val2 is 32-bit variable, val3 is 8-bit variable, and val4 is 8-bit variable. - You need to implement the expression the way it is provided, you cannot do any reduction on the expression while implementing it.- Initialize val1 with 12 (decimal), val2 with 9 (decimal), val3 with 2 (decimal), val4 with 20 (decimal),- You are NOT allowed to update the values stored in val1, val2, val3 and val4- Use mov, add, sub, movsx, movzx, or neg instructions whenever needed.- Use the debugger to verify your answer the format should be .data .code main proc main ENDP END main

tuiwper

Given the following code segment in C++, please write its corresponding 68K assembly code. int sum = 0; int c =1; for (unsigned short i = 0; i <= 10; i++) { if (c == 1 ) { sum += i; c = 0; } else { c = 1; } }

Implement the following C code (or python code) in MIPS assembly. Please your understandings in comments for MIPS code line by line C code: int fib(int n){ if (n==0) return 0; else if (n == 1) return 1; else return 2; } python code: def fib(n): if (n==0): return 0 elif (n == 1): return 1 else return 2

In assembly MIPS I need to write a programp the prompts the user for two intergers(in a subroutine – call it twice), calculates the product of the integers (also in a subroutine) and prints the product with simple descriptive text (also in a subroutine). I need to make 3 little subroutines

Implement the following expression in assembly language: result = (val3 + val4) - (val1 – val2) – (30*4)/55- Assume that result,val1, val2, val3 and val4 are 16-bit integer variables- You need to implement the expression the way it is provided, you cannot do any reduction on theexpression while implementing it.- Initialize val1 with 134 (hexadecimal), val2 with 139 (hexadecimal), val3 with 67(hexadecimal) and val4 with 47 (hexadecimal)- You are NOT allowed to update the values of any variables.- Use ONLY mov, add, sub, movzx, movsx, or neg instructions whenever needed.- Use the debugger to verify your answer

Implement the following expression in assembly language: result = (val3 + val4) (vall - val2) (30*4)/55 Assume that result, vall, val2, val3 and val4 are 16-bit integer variables You need to implement the expression the way it is provided, you cannot do any reduction on the expression while implementing it. - Initialize vall with 134 (hexadecimal), va12 with 139 (hexadecimal), val3 with 67 (hexadecimal) and val4 with 47 (hexadecimal) -