I This program determines whether the user's input is a single What is wrong with the following pseudocode? Il digit. Declare Integer digit I1 Get the input from the user. Display "Enter a single digit." Input digit // Determine if the input is a single digit. If isDigit (digit[0]) AND length(digit) == 1 Then Display digit, " is a single digit." Else Display digit, " is NOT a single digit." End If

Python code of part b please

-Prompts the user to enter an integer x. Assume without error checking the user enters a positive integer. -The program then will print all the odd integers between 1 and x that are a multiple of 3. Sample: Enter an integer x: 15 3 is a multiple of 3 9 is a multiple of 3 15 is a multiple of 3

correct all errors.

Python programming This example misses indentations, rewrite the code. Insert the missing indentation to make the code correct: if 1 == 1:print("One is equal to one!") --------------------------------------------------------------------------------------------------------------------------- Print "Python" if x is not equal to y. x = 2y = 10_____________print("Python") Thank you so much!!

user's input. How could the algorithm be improved so the user does not have to pay End While attention to capitalization when entering a name? 77 This program asks the user to enter a string // and validates the input. Declare String choice // Get the user's response. Display "Cast your vote for Chess Team Captain." Display "Would you like to nominate Lisa or Tim?" Input choice %3D // Validate the input. While choice != "Lisa" AND choice != "Tim" Display "Please enter Lisa or Tim." Display "Cast your vote for Chess Team Captain." Display "Would you like to nominate Lisa or Tim?" Input response End While

Output reput.

What is the Pseudocode?

Python code please help, indentation would be greatly appreciated