Given the following linked list where each node has a data I link field & uses he painters plipz,p3,P Draw a Simikr diagiam to show how this ponfiguration ghanges when the givey spgment of Code epecuts. (Assume each part is independent from Hle other, a p3=P2; p4 link= p2.links execeutes, b) p3.link=p2.link; p2.link pr. link; py. link = p3. link; p4. a parlink= p3; pi. link.linkpl; pi. link. link=pa.link; p4=noll; pa= p4;

/** * This class will use Nodes to form a linked list. It implements the LIFO * (Last In First Out) methodology to reverse the input string. * **/ public class LLStack { private Node head; // Constructor with no parameters for outer class public LLStack( ) { // to do } // This is an inner class specifically utilized for LLStack class, // thus no setter or getters are needed private class Node { private Object data; private Node next; // Constructor with no parameters for inner class public Node(){ // to do // to do } // Parametrized constructor for inner class public Node (Object newData, Node nextLink) { // to do: Data part of Node is an Object // to do: Link to next node is a type Node } } // Adds a node as the first node element at the start of the list with the specified...

Assume you have a class SLNode representing a node in a singly-linked list and a variable called list referencing the first element on a list of integers, as shown below: public class SLNode { private E data; private SLNode next; public SLNode( E e){ data = e; next = null; } public SLNode getNext() { return next; } public void setNext( SLNoden){ next = n; } } SLNode list; Write a fragment of Java code that would append a new node with data value 21 at the end of the list. Assume that you don't know if the list has any elements in it or not (i.e., it may be empty). Do not write a complete method, but just show a necessary fragment of code.

class BSTNode { int key; BSTNode left, right; public BSTNode(int item) { key = item; left = right = null; } } class BST_Tree { BSTNode root; BST_Tree() { // Constructor root = null; } boolean search(int key){ return (searchRec(root, key) != null); } public BSTNode searchRec(BSTNode root, int key) { if (root==null || root.key==key) return root; if (root.key > key) return searchRec(root.left, key); return searchRec (root.right, key); } void deleteKey(int key) { root = deleteRec(root, key); } /* A recursive function to insert a new key in BST */ BSTNode deleteRec(BSTNode root, int key) { /* Base Case: If the tree is empty */ if (root == null) return root; /* Otherwise, recur down the tree */ if (key < root.key)...

1 Assume some Node class with info & link fields. Complete this method in class List that returns a reference to the node containing the data item in the argument find This, Assume that find this is in the list public class List { protected Node head; protected int size; fublic Public Node find (char find This)

For any element in keysList with a value greater than 50, print the corresponding value in itemsList, followed by a comma (no spaces). Ex: If the input is: 32 105 101 35 10 20 30 40 the output is: 20,30, 1 #include 2 3 int main(void) { const int SIZE_LIST = 4; int keysList[SIZE_LIST]; int itemsList[SIZE_LIST]; int i; 4 6 7 8 scanf("%d", &keysList[0]); scanf ("%d", &keysList[1]); scanf("%d", &keysList[2]); scanf("%d", &keysList[3]); 10 11 12 13 scanf ("%d", &itemsList[0]); scanf ("%d", &itemsList[1]); scanf("%d", &itemsList[2]); scanf ("%d", &itemsList[3]); 14 15 16 17 18 19 /* Your code goes here */ 20 21 printf("\n"); 22 23 return 0; 24 }

The numbers on the left margin denote line numbers. line#01 class LL_node {02 int val;03 LL_node next;04 public LL_node (int n) {05 val = n;06 next = null;07 }08 public void set_next (LL_node nextNode) {09 next = nextNode;10 }11 public LL_node get_next () {12 return next;13 }14 public void set_value (int input) {15 val = input;16 }17 public int get_value () {18 return val;19 }20 }21 public class LL {22 protected LL_node head;23 protected LL_node tail;24 public LL () {25 head = null;26 tail = null;27 }28 public int append (int n) {29 if (head == null) {30 head = new LL_node(n);31 tail = head;32 } else {33 LL_node new_node;34 new_node = new LL_node(n);35 tail.set_next (new_node);36 tail = new_node;37 }38 return n;39 }40 } which the following statement...

class BSTNode { int key; BSTNode left, right; public BSTNode(int item) { key = item; left = right = null; } } class BST_Tree { BSTNode root; BST_Tree() { // Constructor root = null; } boolean search(int key){ return (searchRec(root, key) != null); } public BSTNode searchRec(BSTNode root, int key) { if (root==null || root.key==key) return root; if (root.key > key) return searchRec(root.left, key); return searchRec (root.right, key); } void deleteKey(int key) { root = deleteRec(root, key); } /* A recursive function to insert a new key in BST */ BSTNode deleteRec(BSTNode root, int key) { /* Base Case: If the tree is empty */ if (root == null) return root; /* Otherwise, recur down the tree */ if (key < root.key)...

Redesign LaptopList class from previous project public class LaptopList { private class LaptopNode //inner class { public String brand; public double price; public LaptopNode next; public LaptopNode(String brand, double price) { // add your code } public String toString() { // add your code } } private LaptopNode head; // head of the linked list public LaptopList(String fname) throws IOException { File file = new File(fname); Scanner scan = new Scanner(file); head = null; while(scan.hasNextLine()) { // scan data // create LaptopNode // call addToHead and addToTail alternatively } } private void addToHead(LaptopNode node) { // add your code } private void addToTail(LaptopNode node) { // add your code } private...

class Queue { private static int front, rear, capacity; private static int queue[]; Queue(int c) { front = rear = 0; capacity = c; queue = new int[capacity]; } static void queueEnqueue(int data) { if (capacity == rear) { System.out.printf("\nQueue is full\n"); return; } else { queue[rear] = data; rear++; } return; } static void queueDequeue() { if (front == rear) { System.out.printf("\nQueue is empty\n"); return; } else { for (int i = 0; i < rear - 1; i++) { queue[i] = queue[i + 1]; } if (rear < capacity) queue[rear] = 0; rear--; } return; } static void queueDisplay() { int i; if (front == rear) { System.out.printf("\nQueue is Empty\n"); return; } for (i = front; i < rear; i++) { System.out.printf(" %d <-- ", queue[i]); } return; } static void queueFront() { if (front == rear) { System.out.printf("\nQueue is Empty\n"); return; } System.out.printf("\nFront Element is: %d", queue[front]);...

8. Following is the node class: class node { int v node *next: public: node(int x) {v=x; next3D03;} friend class list: }3; Implement the sequential list class below: class list { // circular list class // head position node *head; public: bool empty() { return !head;} list() {head-0;} ~list(); void add(int x); int get(); // empty list judgment / constructor // destructor, to be implemented // add to tail, to be implemented // get from head, to be implemented }3B

class BSTNode { int key; BSTNode left, right; public BSTNode(int item) { key = item; left = right = null; } } class BST_Tree { BSTNode root; BST_Tree() { // Constructor root = null; } boolean search(int key){ return (searchRec(root, key) != null); } public BSTNode searchRec(BSTNode root, int key) { if (root==null || root.key==key) return root; if (root.key > key) return searchRec(root.left, key); return searchRec (root.right, key); } void deleteKey(int key) { root = deleteRec(root, key); } /* A recursive function to insert a new key in BST */ BSTNode deleteRec(BSTNode root, int key) { /* Base Case: If the tree is empty */ if (root == null) return root; /* Otherwise, recur down the tree */ if (key < root.key)...

Data structure Java