// Finds all duplicate elements in the array. for (int i = 1; i <= arrSize; i++) { for (int j = i+1; j <= arrSize; j++) { // if a duplicate is found then increment counter by if (arr[i] == arr[j]) { totalNumofDuplicates++; hreak:

using R language solve the following question

Nested Loops with Addition Principle This algorithm lists the number of strings formed from the symbols in set D (defined below) of length 4 or less with repetitions allowed. Count the number of operations in each loop and determine the total number of operations. Let D = a set of distinct symbols where |D| = 12. for x = D do print x for x = D do for y ED do print xy for x ED do for y ED do for 2 ED do print xyz for a ED do for y ED do for z E D do for q E D do print xyzq

How can a coder escape an endless loop?

A thoroughly thought-out algorithm should be clear of ambiguity.