Find the logic error(s) in the following recursive function, and explain how to correct it (them). This function should find the sum of the values from 0 to n. In [3]: def sum(n): if n == 0: ...: return 0 else: return n + sum(n)

There are two important parts to every simple recursive function: the base case, and the recursive call that makes progress towards the base case. Something that can go wrong with recursion when it is used incorrectly is a stack overflow. Explain two different ways that a recursive function could be written incorrectly that could lead to stack overflow. Hint: one has something to do with the base case, and the other with the recursive call. 1. Enter your answer here 2. Enter your answer here

Write a recursive form of the following: 0! = 1 n! = n * (n - 1)!

Determine the output of the following recursive function when n = 64. (show your working/steps) int func (int n) { if (n ==1) return 0 else return 2 + func ( ) }

Solve the recursion by substitution: T(n) = 3T(n/2)+ 5n where T(1)=1

Recursion efficiency in Julia can be improved using memorization technique to store the values of previously computed functions. The following Fibonacci function below does not employ memorization, please change into a recursive function with memorization: function fib(n) if n==1 return 1 elseif n==2 return 1 elseif n<=0 printstyled("Invalid input",color=:red) return else return fib(n-1)+fib(n-2) end end

Answer the given question with a proper explanation and step-by-step solution.

2. Consider the following function: def func1(n): output = 1 for i in range (1, n) : output = i return output Rewrite the function as a recursive function.

What does the following recursive function do? int f(int n){ if (n==1) return 1; else returm n*f(n-1); } O sum of numbers from 1 to n Factorial of numbern Square of numbers from 1 to n Print the numbers from 1 to n

1. Consider the following recursive function: def foo(n): if (n == 0): return 0 return n + foo(n - 1)a. What is foo(5) b. What is foo(10) c. Suppose that n + foo(n - 1) is changed to n * foo(n - 1). What is foo(5) now? d. What happens if foo(-1) is called?

hi,it is wrong agai n fib(n) 2 1 2 1 2 1 2 1 2 1Number of recursive calls: 5 but have to:

Given the recursive function definition:s(n) = 5 + n * s(n-1) + s(n-2) s(0) = 1 s(1) = 3Question: Evaluate: s(3)

Suppose a recursive function f(n+1)=f(n)+3 and f(3)=10. What is the value of f(5)