Database System Concepts
Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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- Thank you for responding that fast but the same problem occurs after changing the program. This specific message appears: Syntax error (unicode error) 'unicodeescape' codec can't decode bytes in position 2-3: truncated \UXXXXXXXX escape And it highlights the point of: .convert_alpha()arrow_forwardproblem is attached! I am completely stuck! I really need help! please and thank you so much!arrow_forward* All the calculated answers must show the calculation procedure. * Submit printed (e.g., no hand-writing) hard copy before the class on the due date. 1. (1) Sketch the binary encoding and Manchester encoding for the bit stream: 0101110100.arrow_forward
- For each of the following modes, write the numeric equivalent (e.g., 777):a. rw-r--r- -b. r--r- -r- -c. ---rwxrw d.-wxr-xrw e.rw-rw-rwxf. -w-r-- - - -arrow_forward1. Please help me answer this engineering questionarrow_forward5. Hamming Codes a) Suppose we want an error correcting code that will allow all single-bit errors to be corrected for memory words of length 15. How many check bits are necessary? b) Suppose we are now working with memory words of length 8. We have already calculated that we need 4 check bits, and the length of all codewords will be 12. We now receive the following code word: 010011011111 Is this a legal codeword, assuming even parity? If not, where is the error?arrow_forward
- As the error-detection and correction capability of a code increases, we would expect in general the overhead bits to protect a group of data bits to decrease remain the same increasearrow_forwardRefer to figure 8 and enter the decimal value for the Sequence number starting at offset 0x26 (length 4- bytes). .......! pMo...E. .(..@... .f...1.. %M.X.$P. 0000 do do fd c4 09 94 00 21 70 4d 4f ae 08 00 45 00 00 28 19 8е 40 00 80 06 fa 66 се a8 1е бс cd bc За ба 06 9а өө 8f f6 a5 0010 0020 25 4d c6 58 ob 24 50 11 0030 fb 8e d8 dø 00 o0 00 00 00 00 00 00 Figure 8 Byte Details Question 37 Refer to figure 6 and enter the binary bits which represents "only" the IP header length. dø do fd c4 09 94 00 21 00 28 19 8e 40 00 80 06 .......! pMO...E. .(..@... .f...1.. %M.X.$P. 0000 70 4d 4f ae 08 00 45 00 0010 fa 66 сө а8 1е бс cd bc 0020 За 0а 06 9а Ө0 8f f6 a5 25 4d c6 58 ob 24 50 11 0030 fb 8e d8 dø ø0 ø0 00 00 00 00 00 00 Figure 6 Byte Details Question 41 Complete the command to scan the subnet 130.101.108.0:arrow_forwardThis is computer architecture! PLEASE HELP ME FIX THE CODE AS THERE IS ERROR! # This program corrects bad data using Hamming codes # It requests the user to enter a 12-bit Hamming code and determines if it is correct or not # If correct, it displays a message to that effect. If incorrect, it displays a message # saying it was incorrect and what the correct data is (the 12-bit Hamming code) again in hex. # This program is designed to handle single bit errors only. .data prompt: .asciiz "Enter a 12-bit Hamming code: " correct_msg: .asciiz "The Hamming code is correct." incorrect_msg: .asciiz "The Hamming code is incorrect. The correct code is: " newline: .asciiz "\n" .text .globl main main: # Display prompt to enter Hamming code li $v0, 4 la $a0, prompt syscall # Read Hamming code from user li $v0, 5 syscall move $t0, $v0 # Calculate parity bits andi $t1, $t0, 0b1111 # Parity bit p1 andi $t2, $t0, 0b011001100110 # Parity bit p2...arrow_forward
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