Do not use static variables to implement recursive methods. USING JAVA Indicate the order of the following growth functions using < (e.g. n < n2) n2 log n n n2/ log n n! (1.5)n 3n

in java Revers an Array of n integers Reversing an Array1. Describe the definition of recursive function.oBase case(s)oRecursive case(s)2. Write the code.

One remarkably simple formula for calculating the value of p is the so-called Madhava-Leibniz series: p4 =わ 1-ひく13+たす15-ひく17+たす19-.... Consider the recursive function below to calculate the first n terms of this formula: double computePI(int n) { if (n <= 1) { return 1.0;} int oddnum = 2 * n - 1; if ((n % 2) == 0 { } return -1.0 oddnum + computePI(n − 1); } else { } return 1.0 / oddnum + computePI (n - 1); Which statements about the run-time performance of this function are true? 1.Each time this function is called it will invoke at least two more recursive calls II.The number of recursive calls this function will make is approximately equal to the value of the parameter variable n III.Not counting overhead, this function will be about as efficient as an iterative implementation of the same formula

python not java please

Write code to complete raise_to_power(). Note: This example is for practicing recursion; a non-recursive function, or using the built-in function math.pow(), would be more common.Sample output with inputs: 4 24^2 = 16 def raise_to_power(base_val, exponent_val): if exponent_val == 0: result_val = 1 else: result_val = base_val * ''' Your solution goes here ''' return result_val user_base = int(input())user_exponent = int(input()) print('{}^{} = {}'.format(user_base, user_exponent, raise_to_power(user_base, user_exponent)))

Write a recursive function (Java) called Fac which takes one positive integer argument (n) and returns n! You may not use a built-in factorial method or function.

Which is the base case of the following recursion function: def mult3(n): if n == 1: return 3 else: return mult3(n-1) + 3 else n == 1 mult3(n) return mult3(n-1) + 3

The Tower of Hanoi is a puzzle where n disks of different sizes arestacked in ascending order on one rod and there are two other rods with nodisks on them. The objective is to move all disks from the first rod to thethird, such that:- only one disk is moved at a time- a larger disk can never be placed on top of a smaller oneWrite a recursive function that outputs the sequence of steps needed tosolve the puzzle with n disks.Write a test program in C++ that allows the user to input number of disks andthen uses your function to output the steps needed to solve the puzzle.Hint: If you could move up n−1 of the disks from the first post to thethird post using the second post as a spare, the last disk could be moved fromthe first post to the second post. Then by using the same technique you canmove the n−1 disks from the third post to the second post, using the firstdisk as a spare. There! You have the puzzle solved. You only have to decidewhat the nonrecursive case is, what the recursive...

Using recursion, write a function sum that takes a single argument n and computes the sum of all integers between 0 and n inclusive. Do not write this function using a while or for loop. Assume n is non-negative. def sum(n): """Using recursion, computes the sum of all integers between 1 and n, inclusive. Assume n is positive.>>> sum(1) 1>>> sum(5) # 1 + 2 + 3+ 4+ 5 15 "*** YOUR CODE HERE ***"

Which is the base case for the following recursive function? void printOut( int n ) // Print nonnegative n { if( n >= 10 ) printOut( n / 10 ); printDigit( n % 10 ); } Group of answer choices A.if ( n >= 10 ) B.printOut( n/10 ); C.printDigit( n%10 ); D.if ( n >= 10) E.None of the above

in c++ with pre and post pseudocode please dont show me the same code from others please thank u Write the simplest program that will demonstrate iteration vs recursion using the following guidelines - Write two primary helper functions - one iterative (IsArrayPrimeIter) and one recursive (IsArrayPrimeRecur) - each of which Takes an array of integers and its size as input params and returns a bool such that 'true' ==> all elements of the array are prime, so the array is prime, 'false' ==> at least one element in array is not prime, so array is not prime. Print out a message "Entering <function_name>" as the first executed statement of each function. Perform the code to test whether every element of the array is a Prime number. Print out a message "Leaving <function_name>" as the last executed statement before returning from the function. Remember - there will be nested loops for the iterative function and there can be no loops at all in the recursive function....

What does the following recursive function do? int f(int n){ if (n==1) return 1; else returm n*f(n-1); } O sum of numbers from 1 to n Factorial of numbern Square of numbers from 1 to n Print the numbers from 1 to n