Define a function StartsWith() that has two string parameters. If the first string starts with the second string, the function prints the first string followed by "%" and the second string. Otherwise, the function prints "Failed to match.". End with a newline. The function does not return any value. Ex: If the input is dissert dis, then the output is: dissert%dis Note: userText.find("xy") returns the index of the first occurrence of "xy" in userText, or string::npos if userText does not contain "xy". 1 #include 2 using namespace std; 3 4* Your code goes here */ 5 6 int main() { 7 int i; 8 9 10 11 12 13 string inputString1; string inputString2; cin >> inputString1; cin >> inputString2; 14 StartsWith(inputString1, inputString2); 15 16 return 0;

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The countSubstring function will take two strings as parameters and will return an integer that is the count of how many times the substring (the second parameter) appears in the first string without overlapping with itself. This method will be case insensitive. For example: countSubstring("catwoman loves cats", "cat") would return 2 countSubstring("aaa nice", "aa") would return 1 because "aa" only appears once without overlapping itself. public static int countSubstring(String s, String x) { if (s.length() == 0 || x.length() == 0) return 1; if (s.length() == 1 || x.length() == 1){ if (s.substring(0,1).equals(x.substring(0,1))){ s.replaceFirst((x), " "); return 1 + countSubstring(s.substring(1), x); } else { return 0 + countSubstring(s.substring(1), x); } } return countSubstring(s.substring(0,1), x) + countSubstring(s.substring(1), x); } public class Main { public static void main(String[] args) { System.out.println(Recursion.countSubstring("catwoman loves cats","cat"));...

Python question, please us a docstring and have comments throughout code Write a function getInteger() that takes two integers num1 and num2 as parameters. If num1 > num2, then the function prints an error message and returns 0. If num1 is equal to num2, the function returns the common value. For cases where num1 < num2, the function prompts the user to enter an integer greater than or equal to num1 and less than or equal to num2 and returns the first valid integer that the user enters. If the user enters something that is not an integer value, the programs should display an error message and re-prompt the user to enter a valid integer Below are some sample executions of the function. Use the while and if-elif statements and a try/except in the solution. Don’t forget to include the docstring and comments. Copy and paste or screen shot the code and the thirteen test cases shown below in your submission. . >>> getInteger(5,4) 5 and 4 are not valid parameters 0...

Using Racket: Create a function that takes a string and outputs true if the string’s first three letters start with "ppp" ; ppp-question?

Examples Input 8 Output How about visiting Gibraltar Rock? It is about 8 miles away. Input 30 Output How about visiting Oxnard? It is about 30 miles away. Input 120 Output You provided an invalid distance that is not between 0 and 100 miles. Input -100 Output You provided an invalid distance that is not between 0 and 100 miles. Hints • you can check the type of an input parameter by using the type () function.

In C language / Please don't use (sprint) function. Write a function fact_calc that takes a string output argument and an integer input argument n and returns a string showing the calculation of n!. For example, if the value supplied for n were 6, the string returned would be 6! 5 6 3 5 3 4 3 3 3 2 3 1 5 720 Write a program that repeatedly prompts the user for an integer between 0 and 9, calls fact_calc and outputs the resulting string. If the user inputs an invalid value, the program should display an error message and re-prompt for valid input. Input of the sentinel -1 should cause the input loop to exit. Note: Don't print factorial of -1, or any number that is not between 0 and 9. SAMPLE RUN #4: ./Fact Interactive Session Hide Invisibles Highlight: None Show Highlighted Only Enter·an·integer·between·0·and·9·or·-1·to·quit:5↵ 5!·=·5·x·4·x·3·x·2·x·1·x··=·120↵ Enter·an·integer·between·0·and·9·or·-1·to·quit:6↵ 6!·=·6·x·5·x·4·x·3·x·2·x·1·x··=·720↵...

Please help! There is a bug in my program that causes it to jump to the notfound function before checking the entire substring The program should determine whether the second string is a substring of the first. If it is, then the program should print out the first index in which the second string appears in the first. As an example, if the first string is "Hello World" and the second string is "lo", then the program should print out 3, i.e. the starting index of "lo" in "Hello World." If the second string is not contained in the first string, then the program should print out -1. Here is the code: .datastr1: .space 51 #space for str1 (max50 characters including null terminator)str2: .space 51 #space for str2 (max50 characters incl null terminator)msg1: .asciiz "Please enter the first string: " #prompt user to enter str1msg2: .asciiz "Please enter the second string: " #prompt user to enter str2newline: .asciiz "\n" .text.globl mainmain: # Print sttr1 li $v0, 4 la $a0, msg1...

Create a function that will test if a string is a valid PIN or not via a regular expression. A valid PIN has: Exactly 4 or 6 characters. Only numeric characters (0-9). • No whitespace. Examples validate("121317") → true validate("1234") → true validate("45135") → false validate("89abc1") → false validate("900876") → true validate(" 4983") false

Consider the following line of code: X = new int*[n]; What should the type of x be? O int O int* O int** O int& O None of the above

Complete the rotate_text() function that takes 2 parameters, a string data and an integer n. If n is positive, then the function will shift all the characters in data forward by n positions, with characters at the end of the string being moved to the start of the string. If n is 0 then the text remains the same. For example: rotate_text('abcde', rotate_text('abcde', rotate_text('abcde', 1) would return the string 'eabcd' 3) would return the string 'cdeab' 5) would return the string 'abcde' rotate_text('abcde', 6) would return the string 'eabcd' ... and so on. If n is negative, then the function will shift the characters in data backward by n positions, with characters at the start of the string being moved to the end of the string. For example: rotate text('abcde', -1) would return the string 'bcdea'

Instructions There are four clubs in Tesset University South, North, West, and East. A Tesset student can choose to join any number of clubs. Your task is to determine how many students are enrolled in exactly two clubs. Write a function/method named dualClubCounter that will accept a string containing the student number and his desired club. Return a set containing the name of students are enrolled exactly in two clubs. Use SET in your solution Example #1 INPUT: "12300:East,12301:West, 12302:South, 12300:West, 123 Expected Content of Set = [12300] Example #2 INPUT: "12300:East,12301:West, 12302:South, 12300:West,123 Expected Content of Set = [12300, 12301]

please code in pythonis_phone_num: This Boolean function takes a string and returns True if it is in the formatddd-ddd-dddd, where d is a digit, False otherwise. Example calls:is_phone_num('123-456-7890') --> Trueis_phone_num('123-4556-7890') --> Falseis_phone_num('(123)456-7890') --> False