Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN: 9780133594140
Author: James Kurose, Keith Ross
Publisher: PEARSON
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[画像:Assume class LinkedQueue has been defined using the implementation in your textbook that myQueue has been initialized so it is empty. Type the EXACT output of the following code segment. You may assume that the code compiles and executes without errors. ```cpp LinkedQueue<int> myQueue; int i = 1; int j = 2; int k = 3; int n = 4; myQueue.enqueue(n); myQueue.enqueue(j); i = myQueue.peekFront(); myQueue.dequeue(); myQueue.enqueue(k); n = myQueue.peekFront(); myQueue.dequeue(); myQueue.enqueue(j); myQueue.enqueue(n); while (!myQueue.isEmpty()) { i = myQueue.peekFront(); myQueue.dequeue(); cout << i << " "; } cout << endl; ``` ### Explanation 1. **Initialization and Enqueue Operations:** - The integer variables `i`, `j`, `k`, and `n` are initialized. - The queue `myQueue` is initially empty. - Enqueues `4` (value of `n`) and `2` (value of `j`) into `myQueue`. 2. **Peek and Dequeue Operations:** - Peeks the front of the queue, which is `4`, and assigns it to `i`. - Dequeues the front, removing `4`. - Enqueues `3` (value of `k`). 3. **Further Operations:** - Peeks the front, which is now `2`, and assigns it back to `n`. - Dequeues `2`. - Enqueues `2` and then `2` again (current value of `n`). 4. **Output:** - The while loop prints all elements from the front, dequeuing each after printing. - The final print order corresponds to the sequence of elements enqueued: `3`, `2`, `2`. **Exact Output:** ``` 3 2 2 ```]
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Transcribed Image Text:Assume class LinkedQueue has been defined using the implementation in your textbook that myQueue has been initialized so it is empty. Type the EXACT output of the following code segment. You may assume that the code compiles and executes without errors. ```cpp LinkedQueue<int> myQueue; int i = 1; int j = 2; int k = 3; int n = 4; myQueue.enqueue(n); myQueue.enqueue(j); i = myQueue.peekFront(); myQueue.dequeue(); myQueue.enqueue(k); n = myQueue.peekFront(); myQueue.dequeue(); myQueue.enqueue(j); myQueue.enqueue(n); while (!myQueue.isEmpty()) { i = myQueue.peekFront(); myQueue.dequeue(); cout << i << " "; } cout << endl; ``` ### Explanation 1. **Initialization and Enqueue Operations:** - The integer variables `i`, `j`, `k`, and `n` are initialized. - The queue `myQueue` is initially empty. - Enqueues `4` (value of `n`) and `2` (value of `j`) into `myQueue`. 2. **Peek and Dequeue Operations:** - Peeks the front of the queue, which is `4`, and assigns it to `i`. - Dequeues the front, removing `4`. - Enqueues `3` (value of `k`). 3. **Further Operations:** - Peeks the front, which is now `2`, and assigns it back to `n`. - Dequeues `2`. - Enqueues `2` and then `2` again (current value of `n`). 4. **Output:** - The while loop prints all elements from the front, dequeuing each after printing. - The final print order corresponds to the sequence of elements enqueued: `3`, `2`, `2`. **Exact Output:** ``` 3 2 2 ```
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