addDelimiter: public static java.lang.String addDelimiter​(java.lang.String str, char delimeter) Returns a string where characters are separated by the specified delimeter character. A string with a single character will not have a delimeter added. The space character is consider a character (similar to character 'A'). You can assume str will never be the empty string. You may not use an auxiliary method in order to implement this method. Your implementation must be recursive and you may not use any loop construct. Note: In java given two characters a and b, a + b will not create a string. To create a string, append a to the empty string and the result to b. From the String class, the only methods you can use are length(), isEmpty(), charAt() and substring. Do not use ++ or -- in any recursive call argument. It may lead to an infinite recursion. For example, use index + 1, instead of index++. Parameters: str - delimeter - Returns: String with characters separated by delimiter or the original str if the string has a single character

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Practice / Frequency of Characters Write a method that returns the frequency of each characters of a given String parameter. If the given String is null, then return null If the given String is empty return an empty map Example input: output: empty map explanation: input is empty Example input: null output: null explanation: input is null. Since problem output is focused on the frequency we can comfortably use Map data structure. Because we can use characters as key and the occurrences of them as value. Example input: responsible output: {r=1, e=2, s=2, p=1, o=1, n=1, i=1, b=1, l=1} explanation: characters are keys and oc values ences are

Integer userValue is read from input. Assume userValue is greater than 1000 and less than 99999. Assign tensDigit with userValue's tens place value. Ex: If the input is 15876, then the output is: The value in the tens place is: 7 2 3 public class ValueFinder { 4 5 6 7 8 9 10 11 12 13 GHE 14 15 16} public static void main(String[] args) { new Scanner(System.in); } Scanner scnr int userValue; int tensDigit; int tempVal; userValue = scnr.nextInt(); Your code goes here */ 11 System.out.println("The value in the tens place is: + tensDigit);

JAVA PPROGRAM ASAP Please create this program ASAP BECAUSE IT IS MY LAB ASSIGNMENT #2 so it passes all the test cases. The program must pass the test case when uploaded to Hypergrade. Chapter 9. PC #8. 8. Sum of Numbers in a String (page 610) Write a program that asks the user to enter a series of numbers separated by commas. Here are two examples of valid input: 7,9,10,2,18,6 8.777,10.9,11,2.2,-18,6 The program should calculate and display the sum of all the numbers. Input Validation 1. Make sure the string only contains numbers and commas (valid symbols are '0'-'9', '-', '.', and ','). 2. If the string is empty, a messages should be displayed, saying that the string is empty. Test Case 1 Enter a series of numbers separated only by commas or type QUIT to exit:\n7,9,10,2,18,6ENTERThe sum of those numbers is 52.00\nEnter a series of numbers separated only by commas or type QUIT to exit:\nENTEREmpty string.\nEnter a series of numbers separated only by...