1. Generate a number of random integer values within a given range Requirements: - Ask the user the following info: a. How many random numbers they would like to have b. What is the upper and lower limit (e.g. range)? - Generate that many random numbers within that given range - Do not accept negative values for the count, lower or upper limit Help: Here is a simple example on how to generate one random number #include #include using namespace std; int main() { /* get the current system time and use it as the seed to generate*/ srand( time(0) ) ; /* retrieve the next random number */ int num = rand() ; /* print it out */ cout << "Random number: " << num << endl; return 0 ; } Note: you need to call "srand" only once (e.g. not inside a loop). Extend your random generating program to make sure that the numbers are unique. In another words, if the number has been generated and appear early, it should continue to find the next number until the number is unique. If the count is greater than the range, the program will print out an error message because it is not possible to generate that many unique numbers. Hint: use the array to check whether the number has been generated. Write a function "WantToContinue" that will accept one-character answer. It will return true if the answer is 'Y' or 'y' and false otherwise. Use this function in the above program to continue the next set of random numbers as long as the user wants to continue. in c++

1. Generate a number of random integer values within a given range
Requirements:
- Ask the user the following info:
a. How many random numbers they would like to have
b. What is the upper and lower limit (e.g. range)?
- Generate that many random numbers within that given range
- Do not accept negative values for the count, lower or upper limit

Help: Here is a simple example on how to generate one random number

#include <iostream>
#include <ctime>
using namespace std;

int main()
{
/* get the current system time and use it as the seed to generate*/
srand( time(0) ) ;

/* retrieve the next random number */
int num = rand() ;

/* print it out */
cout << "Random number: " << num << endl;

return 0 ;
}
Note: you need to call "srand" only once (e.g. not inside a loop).

Extend your random generating program to make sure that the numbers are unique. In another words, if the number has been generated and appear early, it should continue to find the next number until the number is unique.

If the count is greater than the range, the program will print out an error message because it is not possible to generate that many unique numbers.

Hint: use the array to check whether the number has been generated.

Write a function "WantToContinue" that will accept one-character answer.
It will return true if the answer is 'Y' or 'y' and false otherwise.
Use this function in the above program to continue the next set of random numbers as long as the user wants to continue.

in c++