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1 Px(x) = -x2/202 σ2π The signal x(t) is applied to the input of the following half-wave rectifier circuit with output y(t): x(t) y(1) a. Assuming an ideal diode, find Fy(y) and py(y) for the output amplitude y = xu(x). b. Assuming a non-ideal diode, find Fy(y) and py(y) for the output amplitude y = (x-0.10)u(x-0.10).

1 Px(x) = -x2/202 σ2π The signal x(t) is applied to the input of the following half-wave rectifier circuit with output y(t): x(t) y(1) a. Assuming an ideal diode, find Fy(y) and py(y) for the output amplitude y = xu(x). b. Assuming a non-ideal diode, find Fy(y) and py(y) for the output amplitude y = (x-0.10)u(x-0.10).

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Algebra & Trigonometry with Analytic Geometry

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN: 9781133382119

Author: Swokowski

Publisher: Cengage

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Question

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The PDF of an amplitude X of a Gaussian signal x(t) is given by:

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Transcribed Image Text:1 Px(x) = -x2/202 σ2π The signal x(t) is applied to the input of the following half-wave rectifier circuit with output y(t): x(t) y(1) a. Assuming an ideal diode, find Fy(y) and py(y) for the output amplitude y = xu(x). b. Assuming a non-ideal diode, find Fy(y) and py(y) for the output amplitude y = (x-0.10)u(x-0.10).

Definition Definition Probability of occurrence of a continuous random variable within a specified range. When the value of a random variable, Y, is evaluated at a point Y=y, then the probability distribution function gives the probability that Y will take a value less than or equal to y. The probability distribution function formula for random Variable Y following the normal distribution is: F(y) = P (Y ≤ y) The value of probability distribution function for random variable lies between 0 and 1.

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