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Add explanation and solution for LeetCode problem 1515 (Find the Minimum Number of Fibonacci Numbers Whose Sum Is K) #50
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...mum Number of Fibonacci Numbers Whose Sum Is K)
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Reviewer's GuideIntroduces a comprehensive Markdown explanation and a new Python greedy solution for LeetCode problem 1515, covering problem breakdown, examples, step-by-step strategy, and complexity analysis, all aligned with repository standards. Class diagram for the greedy Fibonacci decomposition solutionclassDiagram
class Solution {
+findMinFibonacciNumbers(k)
}
class FibonacciGenerator {
+fib_numbers: List[int]
+generate_up_to(k)
}
Solution --> FibonacciGenerator: uses
Flow diagram for the greedy selection process in Fibonacci decompositionflowchart TD
A[Start with target k] --> B[Generate Fibonacci numbers up to k]
B --> C[Set remaining = k]
C --> D[Find largest Fibonacci number <= remaining]
D --> E[Subtract Fibonacci number from remaining]
E --> F[Increment count]
F --> G{Is remaining == 0?}
G -- Yes --> H[Return count]
G -- No --> D
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Actionable comments posted: 2
🧹 Nitpick comments (7)
solutions/1515/01.py (3)
14-19: Tighten Fibonacci generation loop.Remove the redundant loop condition + internal break; compute the predicate once.
Apply:
- # Keep generating Fibonacci numbers until we exceed k - while fib_numbers[-1] <= k: - next_fib = fib_numbers[-1] + fib_numbers[-2] - if next_fib > k: - break - fib_numbers.append(next_fib) + # Keep generating Fibonacci numbers while next ≤ k + while fib_numbers[-1] + fib_numbers[-2] <= k: + fib_numbers.append(fib_numbers[-1] + fib_numbers[-2])
25-35: Optional: allow reusing the same Fibonacci number without multiple passes.Your current single-pass for-loop uses each Fibonacci number at most once (still correct for minimal representation). If you prefer to match the doc phrasing "can be used multiple times," use an inner while to keep subtracting the same term.
Apply:
- for i in range(len(fib_numbers) - 1, -1, -1): - if fib_numbers[i] <= remaining: - remaining -= fib_numbers[i] - count += 1 - - # If we've reached the target, we're done - if remaining == 0: - break + for i in range(len(fib_numbers) - 1, -1, -1): + while remaining >= fib_numbers[i]: + remaining -= fib_numbers[i] + count += 1 + if remaining == 0: + break
1-10: Add type hints and tighten docstring.Small clarity/consistency boost.
Apply:
-def findMinFibonacciNumbers(k): +def findMinFibonacciNumbers(k: int) -> int: """ - Find the minimum number of Fibonacci numbers whose sum equals k. + Compute the minimum count of Fibonacci numbers whose sum equals k. Args: - k: int - Target sum to achieve + k (int): Target sum to achieve. Returns: - int - Minimum number of Fibonacci numbers needed + int: Minimum number of Fibonacci numbers needed. + + Notes: + Time: O(log k); Space: O(log k) — number of Fibonacci numbers ≤ k. """explanations/1515/en.md (4)
3-3: Fix MD034 (bare URL) and align with corrected problem number.Wrap the URL in a link label.
Apply:
-https://leetcode.com/problems/find-the-minimum-number-of-fibonacci-numbers-whose-sum-is-k +[Problem link](https://leetcode.com/problems/find-the-minimum-number-of-fibonacci-numbers-whose-sum-is-k)
16-16: Convert bolded section titles to proper headings (MD036).Use headings for sections instead of bold emphasis.
Apply (illustrative):
-**Examples** +## Examples -**Constraints** +## Constraints -**Step 1: Generate Fibonacci numbers up to k** +#### Step 1: Generate Fibonacci numbers up to k -**Step 2: Greedy selection process** +#### Step 2: Greedy selection process -**Step 3: Result** +#### Step 3: ResultAlso applies to: 36-36, 75-75, 83-83, 97-97
62-67: Minor editorial polish for the numbered list.Add periods and parallel structure for readability.
Apply:
-1. **Generate Fibonacci numbers**: Create all Fibonacci numbers up to `k` -2. **Greedy selection**: Always choose the largest Fibonacci number that fits -3. **Subtract and repeat**: Subtract the chosen number and continue until sum reaches 0 -4. **Count operations**: Track how many Fibonacci numbers were used +1. **Generate Fibonacci numbers**: Create all Fibonacci numbers up to `k`. +2. **Greedy selection**: Choose the largest Fibonacci number that fits. +3. **Subtract and repeat**: Subtract the chosen number; repeat until the sum reaches 0. +4. **Count operations**: Track how many Fibonacci numbers were used.
101-106: Optional: cite the theorem underpinning the greedy choice.A brief nod to Zeckendorf’s theorem strengthens the justification for optimality.
Apply:
-3. **Fibonacci properties**: Each Fibonacci number is the sum of the two preceding ones, making the greedy choice optimal +3. **Fibonacci properties (Zeckendorf’s theorem)**: Every positive integer can be represented as a sum of nonconsecutive Fibonacci numbers, which underpins the optimality of the greedy choice.
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📒 Files selected for processing (2)
explanations/1515/en.md(1 hunks)solutions/1515/01.py(1 hunks)
🧰 Additional context used
🪛 LanguageTool
explanations/1515/en.md
[style] ~48-~48: As an alternative to the over-used intensifier ‘very’, consider replacing this phrase.
Context: ...ven?** A target integer k that can be very large (up to 109). What is being asked? ...
(EN_WEAK_ADJECTIVE)
[grammar] ~59-~59: There might be a mistake here.
Context: ...onacci numbers High-level approach: The solution involves generating Fibonac...
(QB_NEW_EN)
[grammar] ~62-~62: There might be a mistake here.
Context: ... in the remaining sum. Decomposition: 1. Generate Fibonacci numbers: Create all...
(QB_NEW_EN)
[grammar] ~63-~63: There might be a mistake here.
Context: ...s**: Create all Fibonacci numbers up to k 2. Greedy selection: Always choose the la...
(QB_NEW_EN)
[grammar] ~65-~65: There might be a mistake here.
Context: ...Subtract the chosen number and continue until sum reaches 0 4. Count operations: ...
(QB_NEW_EN)
[grammar] ~70-~70: There might be a mistake here.
Context: ...extremely inefficient. - Optimized: Use greedy approach with pre-generated Fibo...
(QB_NEW_EN)
[grammar] ~72-~72: There might be a mistake here.
Context: ...rs. This takes O(log k) time. ### Steps Let's walk through the solution step by ...
(QB_NEW_EN)
[grammar] ~75-~75: There might be a mistake here.
Context: ...ep 1: Generate Fibonacci numbers up to k** - Start with F1 = 1, F2 = 1 - F3 = F2 + F1...
(QB_NEW_EN)
[grammar] ~77-~77: There might be a mistake here.
Context: ...1 = 1, F2 = 1 - F3 = F2 + F1 = 1 + 1 = 2 - F4 = F3 + F2 = 2 + 1 = 3 - F5 = F4 + F3 ...
(QB_NEW_EN)
[grammar] ~78-~78: There might be a mistake here.
Context: ...1 = 1 + 1 = 2 - F4 = F3 + F2 = 2 + 1 = 3 - F5 = F4 + F3 = 3 + 2 = 5 - F6 = F5 + F4 ...
(QB_NEW_EN)
[grammar] ~79-~79: There might be a mistake here.
Context: ...2 = 2 + 1 = 3 - F5 = F4 + F3 = 3 + 2 = 5 - F6 = F5 + F4 = 5 + 3 = 8 (exceeds 7, sto...
(QB_NEW_EN)
[grammar] ~80-~80: There might be a mistake here.
Context: ... = F5 + F4 = 5 + 3 = 8 (exceeds 7, stop) - Fibonacci numbers up to 7: [1, 1, 2, 3, ...
(QB_NEW_EN)
[grammar] ~83-~83: There might be a mistake here.
Context: ..., 5] Step 2: Greedy selection process - Remaining sum: 7 - **Largest Fibonacci...
(QB_NEW_EN)
[grammar] ~84-~84: There might be a mistake here.
Context: ...lection process** - Remaining sum: 7 - Largest Fibonacci ≤ 7: 5 - Use 5: ...
(QB_NEW_EN)
[grammar] ~85-~85: There might be a mistake here.
Context: ... sum**: 7 - Largest Fibonacci ≤ 7: 5 - Use 5: 7 - 5 = 2 - Count: 1 - **R...
(QB_NEW_EN)
[grammar] ~86-~86: There might be a mistake here.
Context: ...ibonacci ≤ 7**: 5 - Use 5: 7 - 5 = 2 - Count: 1 - Remaining sum: 2 - **L...
(QB_NEW_EN)
[grammar] ~89-~89: There might be a mistake here.
Context: ...2 - Count: 1 - Remaining sum: 2 - Largest Fibonacci ≤ 2: 2 - Use 2: ...
(QB_NEW_EN)
[grammar] ~90-~90: There might be a mistake here.
Context: ... sum**: 2 - Largest Fibonacci ≤ 2: 2 - Use 2: 2 - 2 = 0 - Count: 2 - **R...
(QB_NEW_EN)
[grammar] ~91-~91: There might be a mistake here.
Context: ...ibonacci ≤ 2**: 2 - Use 2: 2 - 2 = 0 - Count: 2 - Remaining sum: 0 - **P...
(QB_NEW_EN)
[grammar] ~94-~94: There might be a mistake here.
Context: ...0 - Count: 2 - Remaining sum: 0 - Process complete Step 3: Result -...
(QB_NEW_EN)
[grammar] ~97-~97: There might be a mistake here.
Context: ...- Process complete Step 3: Result - Total Fibonacci numbers used: 2 - Soluti...
(QB_NEW_EN)
[grammar] ~98-~98: There might be a mistake here.
Context: ...sult** - Total Fibonacci numbers used: 2 - Solution: 5 + 2 = 7 Why this works:...
(QB_NEW_EN)
[grammar] ~101-~101: There might be a mistake here.
Context: ...Solution: 5 + 2 = 7 Why this works: The greedy approach works because: 1. **...
(QB_NEW_EN)
[grammar] ~102-~102: There might be a mistake here.
Context: ...ks:** The greedy approach works because: 1. Optimal substructure: If we can repres...
(QB_NEW_EN)
🪛 markdownlint-cli2 (0.17.2)
explanations/1515/en.md
3-3: Bare URL used
(MD034, no-bare-urls)
16-16: Emphasis used instead of a heading
(MD036, no-emphasis-as-heading)
36-36: Emphasis used instead of a heading
(MD036, no-emphasis-as-heading)
75-75: Emphasis used instead of a heading
(MD036, no-emphasis-as-heading)
83-83: Emphasis used instead of a heading
(MD036, no-emphasis-as-heading)
97-97: Emphasis used instead of a heading
(MD036, no-emphasis-as-heading)
🔇 Additional comments (1)
explanations/1515/en.md (1)
6-6: Verify phrasing about reusing the same Fibonacci number.The text says "can be used multiple times." While the greedy solution remains correct, minimal decompositions never need repeats (Zeckendorf). Consider clarifying to avoid confusion with "distinct" wording sometimes seen.
Would you like me to update the sentence to: "You may reuse Fibonacci numbers, although an optimal solution never needs repeats (by Zeckendorf’s theorem)."?
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Critical: Wrong problem number and path.
This page titles the Fibonacci-sum problem as "1515" but that problem is actually 1414 (Medium). Please change the title to "## 1414. ... [Medium]" and move the file to explanations/1414/en.md. Update PR title/labels/links accordingly.
🤖 Prompt for AI Agents
In explanations/1515/en.md around lines 1 to 1, the file and title use the wrong
problem number; change the first line from "## 1515. Find the Minimum Number of
Fibonacci Numbers Whose Sum Is K [Medium]" to "## 1414. Find the Minimum Number
of Fibonacci Numbers Whose Sum Is K [Medium]" and move the file from
explanations/1515/en.md to explanations/1414/en.md, updating any internal
references/relative links in the file; also update the PR title, labels, and any
external links or references in the repo that point to explanations/1515 to
point to explanations/1414 so consistency is preserved.
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Critical: Wrong problem ID/directory (should be 1414, not 1515).
This solution implements LeetCode "Find the Minimum Number of Fibonacci Numbers Whose Sum Is K," which is problem 1414 (Medium), not 1515. Please move the file to solutions/1414/01.py and update any cross-links/metadata accordingly to avoid indexing and navigation issues.
🤖 Prompt for AI Agents
In solutions/1515/01.py lines 1-35, the file implements LeetCode problem 1414
but is placed under directory 1515; move the file to solutions/1414/01.py and
update any repository references (imports, README indices, tests, CI config, or
metadata files) that point to solutions/1515/01.py so they reference
solutions/1414/01.py instead, and remove or replace the incorrect entry under
solutions/1515 to keep indexing/navigation consistent.
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Summary
Add comprehensive explanation and Python solution for LeetCode problem 1515 (Find the Minimum Number of Fibonacci Numbers Whose Sum Is K).
New Features
tex instead oftext for code blocks as requestedDocumentation
Key Implementation Details
Files Added
explanations/1515/en.md- Comprehensive problem explanation with strategy and step-by-step walkthroughsolutions/1515/01.py- Clean Python solution with proper documentationThe solution demonstrates an elegant greedy approach to Fibonacci number decomposition, making it an excellent example for learning greedy algorithms and mathematical problem-solving techniques.
Summary by Sourcery
Add comprehensive markdown explanation and Python solution for LeetCode problem 1515 by generating Fibonacci numbers and using a greedy selection to achieve the target sum
New Features:
Documentation:
Summary by CodeRabbit