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Commit dd840f3

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mzfrmzfr
mzfr
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mzfr
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Solution for drone motion
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‎INShAck-2019/drone/README.md‎

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# Drone Motion
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__DESCRIPTION__
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We intercepted a drone flying above a restricted area and retrieved a [log](https://static.ctf.insecurity-insa.fr/5e97cfb3f4c64201c201a1703440c397f91be74b.tar.gz) from its memory card.
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Help us find out what this drone was doing above our heads!
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Flag must match the regex: INSA\{[a-f0-9]+\}
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__SOLUTION__
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This was a simple one we just simply had to plot the values of x, y, z to get the flag.
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```python
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import re
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import matplotlib.pyplot as plt
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lines = open("sensors.log").readlines()
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coords = []
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x_coords = []
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y_coords = []
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z_coords = []
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cur_X,cur_Y,cur_Z = 0,0,0
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for line in lines:
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match = re.findall("\[drone\]\(DEBUG\)> dir: \(x=(-?\d.\d+),y=(-?\d+.\d+),z=(-?\d.\d+)\)", line)
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if match:
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x,y,z = map(float, match[0])
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cur_X += x
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cur_Y += y
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cur_Z += z
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x_coords.append(cur_X)
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y_coords.append(cur_Y)
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z_coords.append(cur_Z)
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ax = plt.plot(x_coords, y_coords, '-')
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plt.axis('equal')
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plt.savefig("test.png", dpi=1000)
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```
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This would give us the flag
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![alt text](flag.png)
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This challenge was also solved by none other than __@unblvr__
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`P.S` - In starting for some reason we were confused on with `E` and `F` but the later we realized that `F`'s middle line is smaller then `E`'s

‎INShAck-2019/drone/flag.png‎

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‎INShAck-2019/drone/parse.py‎

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import re
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import matplotlib.pyplot as plt
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lines = open("sensors.log").readlines()
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coords = []
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x_coords = []
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y_coords = []
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z_coords = []
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cur_X,cur_Y,cur_Z = 0,0,0
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for line in lines:
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match = re.findall("\[drone\]\(DEBUG\)> dir: \(x=(-?\d.\d+),y=(-?\d+.\d+),z=(-?\d.\d+)\)", line)
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if match:
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x,y,z = map(float, match[0])
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cur_X += x
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cur_Y += y
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cur_Z += z
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x_coords.append(cur_X)
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y_coords.append(cur_Y)
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z_coords.append(cur_Z)
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#print(x,y,z)
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ax = plt.plot(x_coords, y_coords, '-')
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plt.axis('equal')
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#plt.ylim(-500,500)
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plt.savefig("test.png", dpi=1000)

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