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exercism 75- Crypto Square

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`@@ -296,7 +296,7 @@ solution of many challenges of [Leetcode](https://leetcode.com/), [Exercism](htt`
`296`	`296`	`72. [Wordy](https://github.com/kumar91gopi/Algorithms-and-Data-Structures-in-Ruby/blob/master/exercism/wordy.rb)`
`297`	`297`	`73. [Secret Handshake](https://github.com/kumar91gopi/Algorithms-and-Data-Structures-in-Ruby/blob/master/exercism/secret_handshake.rb)`
`298`	`298`	`74. [Atbash Cipher](https://github.com/kumar91gopi/Algorithms-and-Data-Structures-in-Ruby/blob/master/exercism/atbash_cipher.rb)`
`299`		`-`
	`299`	`+75.[Crypto Square](https://github.com/kumar91gopi/Algorithms-and-Data-Structures-in-Ruby/blob/master/exercism/crypto_square.rb)`
`300`	`300`
`301`	`301`	`<a name="leetcode"/>`
`302`	`302`

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	`1`	`+# Problem: https://exercism.org/tracks/ruby/exercises/crypto-square`
	`2`	`+`
	`3`	`+# Solution`
	`4`	`+class Crypto`
	`5`	`+ def initialize(plaintext)`
	`6`	`+ @plaintext = plaintext`
	`7`	`+ end`
	`8`	`+`
	`9`	`+ def ciphertext`
	`10`	`+ normalized_text = @plaintext.downcase.gsub(/\W/,"")`
	`11`	`+ text_len = normalized_text.length`
	`12`	`+ return "" if text_len==0`
	`13`	`+ col_len = Math.sqrt(text_len).ceil`
	`14`	`+ row_len = col_len*(col_len-1) < text_len ? col_len : col_len-1`
	`15`	`+ char_deficit = (col_len*row_len)-text_len`
	`16`	`+ normalized_text+=(" "*char_deficit)`
	`17`	`+ normalized_text`
	`18`	`+ .chars`
	`19`	`+ .each_slice(col_len)`
	`20`	`+ .to_a`
	`21`	`+ .transpose`
	`22`	`+ .map{\|col\| col.join("")}`
	`23`	`+ .join(" ")`
	`24`	`+ end`
	`25`	`+end`
	`26`	`+`
	`27`	`+# Solution (idiomatic)`
	`28`	`+class Crypto`
	`29`	`+ def initialize(plaintext)`
	`30`	`+ @plaintext = plaintext`
	`31`	`+ end`
	`32`	`+`
	`33`	`+ def ciphertext`
	`34`	`+ normalized_text = @plaintext.downcase.gsub(/[^\da-z]/, '')`
	`35`	`+ length = normalized_text.length`
	`36`	`+ return '' if length.zero?`
	`37`	`+ cols = Math.sqrt(length).ceil`
	`38`	`+ rows = length.quo(cols).ceil`
	`39`	`+ rectangle_base = normalized_text + ' ' * (cols * rows - length)`
	`40`	`+ rectangle_base.chars.each_slice(cols).to_a.transpose.map(&:join).join(' ')`
	`41`	`+ end`
	`42`	`+end`

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