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1 | 1 | # `Today Update` |
2 | 2 | (Notes: "♥" Welcome to visit or fork or star my LeetCode Manager @ |
3 | 3 | https://github.com/jackzhenguo/LeetCodeManager |
4 | | -## Sort |
5 | | -### 324 Wiggle Sort II |
6 | | -* [Github:#324 Wiggle Sort II](/Sort/WiggleSortSln.cs) |
7 | | -* [CSDN:#324 Wiggle Sort II](http://blog.csdn.net/daigualu/article/details/72820281) |
8 | | - * This is a great question for it involves a great idea: virtual index |
9 | | - ```C# |
10 | | - /// <summary> |
11 | | - /// WiggleSort |
12 | | - /// </summary> |
13 | | - public class WiggleSortSln |
14 | | - { |
15 | | - private static int[] _array; |
16 | | - |
17 | | - public int[] WiggleSort(int[] array) |
18 | | - { |
19 | | - _array = array; |
20 | | - int median = findKThLargest(_array.Length / 2); |
21 | | - int left = 0, i = 0, right = _array.Length - 1; |
22 | | - |
23 | | - while (i <= right) |
24 | | - { |
25 | | - if (_array[newIndex(i)] > median) |
26 | | - { |
27 | | - //put newIndex(i) at odd index(from 1, 3, to 5, ...) |
28 | | - swap(newIndex(left++), newIndex(i)); |
29 | | - i++; |
30 | | - } |
31 | | - else if (_array[newIndex(i)] < median) |
32 | | - { |
33 | | - //put newIndex(i) at even index(max even index to little .... ) |
34 | | - swap(newIndex(right--), newIndex(i)); //right--, so i relatively toward right 1 step |
35 | | - } |
36 | | - else |
37 | | - { |
38 | | - i++; |
39 | | - } |
40 | | - } |
41 | | - return _array; |
42 | | - } |
43 | | - |
44 | | - private int newIndex(int index) |
45 | | - { |
46 | | - return (1 + 2 * index) % (_array.Length | 1); |
47 | | - } |
48 | 4 |
|
49 | | - private void swap(int i, int j) |
50 | | - { |
51 | | - int tmp = _array[i]; |
52 | | - _array[i] = _array[j]; |
53 | | - _array[j] = tmp; |
54 | | - } |
55 | | - |
56 | | - //based on quick sort to find the Kth largest in _array |
57 | | - private int findKThLargest(int k) |
58 | | - { |
59 | | - int left = 0; |
60 | | - int right = _array.Length - 1; |
61 | | - while (true) |
62 | | - { |
63 | | - int pivotIndex = quickSort(left, right); |
64 | | - if (k == pivotIndex) |
65 | | - return _array[pivotIndex]; |
66 | | - else if (k < pivotIndex) |
67 | | - right = pivotIndex - 1; |
68 | | - else |
69 | | - left = pivotIndex + 1; |
70 | | - } |
71 | | - } |
72 | | - |
73 | | - private int quickSort(int lo, int hi) |
| 5 | +## Bit Mainpulation |
| 6 | +### 461 Hamming Distance |
| 7 | +* [CSDN:#461 Hamming Distance](http://blog.csdn.net/daigualu/article/details/72830624) |
| 8 | + > x&(x-1) application; xor application</br> |
| 9 | + ```C# |
| 10 | + public int HammingDistance(int x, int y) |
74 | 11 | { |
75 | | - int key = _array[lo]; |
76 | | - while (lo < hi) |
| 12 | + ///a and y are different bits, so we think the XOR |
| 13 | + ///think:0001(1D) |
| 14 | + /// 0100(4D) |
| 15 | + ///xor = 0101(1D^4D) |
| 16 | + int dist = 0, xor = x ^ y; |
| 17 | + while (xor > 0) |
77 | 18 | { |
78 | | - while (lo < hi && _array[hi] >= key) |
79 | | - hi--; |
80 | | - //hi is less than key, hi element moves to lo index |
81 | | - _array[lo] = _array[hi]; |
82 | | - while (lo < hi && _array[lo] < key) |
83 | | - lo++; |
84 | | - //lo is bigger than key, lo element moves to hi index |
85 | | - _array[hi] = _array[lo]; |
| 19 | + ///xor & (xor-1): it sets the rightest 1 bit to 0 bit of xor. |
| 20 | + ++dist; |
| 21 | + xor = xor & (xor - 1); |
86 | 22 | } |
87 | | - _array[lo] = key; |
88 | | - return lo; |
| 23 | + return dist; |
89 | 24 | } |
90 | | - } |
91 | | - ``` |
92 | | - ## Bit Mainpulation |
93 | | -### 342 Power of Four |
94 | | -* [Github:#342 Power of Four](/BitManipulation/PowOfFourSln.cs) |
95 | | -* [CSDN:#342 Power of Four](http://blog.csdn.net/daigualu/article/details/72821233) |
96 | | ---- |
| 25 | + ```C# |
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