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Commit 76dc15a

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feat: add solutions to lc problems: No.1596,1831
* No.1596.The Most Frequently Ordered Products for Each Customer * No.1831.Maximum Transaction Each Day
1 parent 7e289d3 commit 76dc15a

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7 files changed

+138
-44
lines changed

7 files changed

+138
-44
lines changed

‎solution/1500-1599/1596.The Most Frequently Ordered Products for Each Customer/README.md‎

Lines changed: 26 additions & 17 deletions
Original file line numberDiff line numberDiff line change
@@ -126,26 +126,35 @@ John (customer 5) 没有订购过商品, 所以我们并没有把 John 包含在
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<!-- tabs:start -->
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### **Python3**
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### **SQL**
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<!-- 这里可写当前语言的特殊实现逻辑 -->
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```python
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```
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### **Java**
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<!-- 这里可写当前语言的特殊实现逻辑 -->
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```java
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```
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### **...**
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```
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```sql
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# Write your MySQL query statement below
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select
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customer_id,
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p.product_id,
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p.product_name
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from
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(
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select
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customer_id,
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product_id,
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rank() over(
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partition by customer_id
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order by
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count(1) desc
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) rk
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from
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Orders
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group by
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customer_id,
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product_id
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) o
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join Products p on o.product_id = p.product_id
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where
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rk = 1;
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```
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<!-- tabs:end -->

‎solution/1500-1599/1596.The Most Frequently Ordered Products for Each Customer/README_EN.md‎

Lines changed: 27 additions & 16 deletions
Original file line numberDiff line numberDiff line change
@@ -122,22 +122,33 @@ John (customer 5) did not order anything, so we do not include them in the resul
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<!-- tabs:start -->
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### **Python3**
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```python
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```
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### **Java**
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```java
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```
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### **...**
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```
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### **SQL**
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```sql
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# Write your MySQL query statement below
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select
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customer_id,
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p.product_id,
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p.product_name
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from
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(
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select
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customer_id,
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product_id,
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rank() over(
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partition by customer_id
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order by
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count(1) desc
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) rk
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from
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Orders
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group by
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customer_id,
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product_id
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) o
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join Products p on o.product_id = p.product_id
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where
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rk = 1;
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```
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<!-- tabs:end -->
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Original file line numberDiff line numberDiff line change
@@ -0,0 +1,24 @@
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# Write your MySQL query statement below
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select
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customer_id,
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p.product_id,
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p.product_name
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from
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(
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select
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customer_id,
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product_id,
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rank() over(
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partition by customer_id
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order by
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count(1) desc
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) rk
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from
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Orders
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group by
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customer_id,
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product_id
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) o
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join Products p on o.product_id = p.product_id
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where
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rk = 1;

‎solution/1800-1899/1831.Maximum Transaction Each Day/README.md‎

Lines changed: 19 additions & 1 deletion
Original file line numberDiff line numberDiff line change
@@ -71,7 +71,25 @@ Result table:
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<!-- 这里可写当前语言的特殊实现逻辑 -->
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```sql
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# Write your MySQL query statement below
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select
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transaction_id
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from
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(
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select
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transaction_id,
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rank() over(
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partition by date_format(day, '%Y-%m-%d')
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order by
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amount desc
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) rk
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from
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Transactions
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order by
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transaction_id
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) t
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where
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rk = 1
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```
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<!-- tabs:end -->

‎solution/1800-1899/1831.Maximum Transaction Each Day/README_EN.md‎

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Original file line numberDiff line numberDiff line change
@@ -67,7 +67,25 @@ We order the result table by transaction_id after collecting these IDs.
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### **SQL**
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```sql
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# Write your MySQL query statement below
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select
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transaction_id
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from
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(
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select
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transaction_id,
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rank() over(
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partition by date_format(day, '%Y-%m-%d')
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order by
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amount desc
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) rk
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from
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Transactions
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order by
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transaction_id
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) t
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where
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rk = 1
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```
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<!-- tabs:end -->
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Original file line numberDiff line numberDiff line change
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# Write your MySQL query statement below
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select
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transaction_id
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from
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(
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select
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transaction_id,
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rank() over(
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partition by date_format(day, '%Y-%m-%d')
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order by
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amount desc
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) rk
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from
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Transactions
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order by
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transaction_id
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) t
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where
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rk = 1

‎solution/2400-2499/2460.Apply Operations to an Array/README.md‎

Lines changed: 4 additions & 9 deletions
Original file line numberDiff line numberDiff line change
@@ -111,15 +111,10 @@ class Solution {
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}
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}
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int[] ans = new int[n];
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int j = 0;
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for (int i = 0; i < n; ++i) {
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if (nums[i] != 0) {
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ans[j++] = nums[i];
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}
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}
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for (int i = 0; i < n; ++i) {
121-
if (nums[i] == 0) {
122-
ans[j++] = nums[i];
114+
int i = 0;
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for (int x : nums) {
116+
if (x > 0) {
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ans[i++] = x;
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}
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}
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return ans;

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