|
58 | 58 |
|
59 | 59 | <!-- 这里可写通用的实现逻辑 --> |
60 | 60 |
|
| 61 | +**方法一:排序** |
| 62 | + |
| 63 | +先计算每个工人和每个自行车之间的曼哈顿距离,然后按照曼哈顿距离从小到大排序,遍历排序后的数组,如果当前工人和自行车都未被分配,则分配给当前工人和自行车。 |
| 64 | + |
| 65 | +时间复杂度 $O(n\times m\times \log (n\times m))$。其中 $n$ 和 $m$ 分别为工人和自行车的数量。 |
| 66 | + |
61 | 67 | <!-- tabs:start --> |
62 | 68 |
|
63 | 69 | ### **Python3** |
64 | 70 |
|
65 | 71 | <!-- 这里可写当前语言的特殊实现逻辑 --> |
66 | 72 |
|
67 | 73 | ```python |
68 | | - |
| 74 | +class Solution: |
| 75 | + def assignBikes(self, workers: List[List[int]], bikes: List[List[int]]) -> List[int]: |
| 76 | + n, m = len(workers), len(bikes) |
| 77 | + arr = [] |
| 78 | + for i, j in product(range(n), range(m)): |
| 79 | + dist = abs(workers[i][0] - bikes[j][0]) + \ |
| 80 | + abs(workers[i][1] - bikes[j][1]) |
| 81 | + arr.append((dist, i, j)) |
| 82 | + arr.sort() |
| 83 | + vis1 = [False] * n |
| 84 | + vis2 = [False] * m |
| 85 | + ans = [0] * n |
| 86 | + for _, i, j in arr: |
| 87 | + if not vis1[i] and not vis2[j]: |
| 88 | + vis1[i] = vis2[j] = True |
| 89 | + ans[i] = j |
| 90 | + return ans |
69 | 91 | ``` |
70 | 92 |
|
71 | 93 | ### **Java** |
72 | 94 |
|
73 | 95 | <!-- 这里可写当前语言的特殊实现逻辑 --> |
74 | 96 |
|
75 | 97 | ```java |
| 98 | +class Solution { |
| 99 | + public int[] assignBikes(int[][] workers, int[][] bikes) { |
| 100 | + int n = workers.length, m = bikes.length; |
| 101 | + int[][] arr = new int[m * n][3]; |
| 102 | + for (int i = 0, k = 0; i < n; ++i) { |
| 103 | + for (int j = 0; j < m; ++j) { |
| 104 | + int dist = Math.abs(workers[i][0] - bikes[j][0]) + Math.abs(workers[i][1] - bikes[j][1]); |
| 105 | + arr[k++] = new int[] {dist, i, j}; |
| 106 | + } |
| 107 | + } |
| 108 | + Arrays.sort(arr, (a, b) -> { |
| 109 | + if (a[0] != b[0]) { |
| 110 | + return a[0] - b[0]; |
| 111 | + } |
| 112 | + if (a[1] != b[1]) { |
| 113 | + return a[1] - b[1]; |
| 114 | + } |
| 115 | + return a[2] - b[2]; |
| 116 | + }); |
| 117 | + boolean[] vis1 = new boolean[n]; |
| 118 | + boolean[] vis2 = new boolean[m]; |
| 119 | + int[] ans = new int[n]; |
| 120 | + for (var e : arr) { |
| 121 | + int i = e[1], j = e[2]; |
| 122 | + if (!vis1[i] && !vis2[j]) { |
| 123 | + vis1[i] = true; |
| 124 | + vis2[j] = true; |
| 125 | + ans[i] = j; |
| 126 | + } |
| 127 | + } |
| 128 | + return ans; |
| 129 | + } |
| 130 | +} |
| 131 | +``` |
| 132 | + |
| 133 | +### **C++** |
| 134 | + |
| 135 | +```cpp |
| 136 | +class Solution { |
| 137 | +public: |
| 138 | + vector<int> assignBikes(vector<vector<int>>& workers, vector<vector<int>>& bikes) { |
| 139 | + int n = workers.size(), m = bikes.size(); |
| 140 | + vector<tuple<int, int, int>> arr(n * m); |
| 141 | + for (int i = 0, k = 0; i < n; ++i) { |
| 142 | + for (int j = 0; j < m; ++j) { |
| 143 | + int dist = abs(workers[i][0] - bikes[j][0]) + abs(workers[i][1] - bikes[j][1]); |
| 144 | + arr[k++] = {dist, i, j}; |
| 145 | + } |
| 146 | + } |
| 147 | + sort(arr.begin(), arr.end()); |
| 148 | + vector<bool> vis1(n), vis2(m); |
| 149 | + vector<int> ans(n); |
| 150 | + for (auto& [_, i, j] : arr) { |
| 151 | + if (!vis1[i] && !vis2[j]) { |
| 152 | + vis1[i] = true; |
| 153 | + vis2[j] = true; |
| 154 | + ans[i] = j; |
| 155 | + } |
| 156 | + } |
| 157 | + return ans; |
| 158 | + } |
| 159 | +}; |
| 160 | +``` |
76 | 161 | |
| 162 | +### **Go** |
| 163 | + |
| 164 | +```go |
| 165 | +func assignBikes(workers [][]int, bikes [][]int) []int { |
| 166 | + n, m := len(workers), len(bikes) |
| 167 | + type tuple struct{ d, i, j int } |
| 168 | + arr := make([]tuple, n*m) |
| 169 | + for i, k := 0, 0; i < n; i++ { |
| 170 | + for j := 0; j < m; j++ { |
| 171 | + d := abs(workers[i][0]-bikes[j][0]) + abs(workers[i][1]-bikes[j][1]) |
| 172 | + arr[k] = tuple{d, i, j} |
| 173 | + k++ |
| 174 | + } |
| 175 | + } |
| 176 | + sort.Slice(arr, func(i, j int) bool { |
| 177 | + if arr[i].d != arr[j].d { |
| 178 | + return arr[i].d < arr[j].d |
| 179 | + } |
| 180 | + if arr[i].i != arr[j].i { |
| 181 | + return arr[i].i < arr[j].i |
| 182 | + } |
| 183 | + return arr[i].j < arr[j].j |
| 184 | + }) |
| 185 | + vis1, vis2 := make([]bool, n), make([]bool, m) |
| 186 | + ans := make([]int, n) |
| 187 | + for _, e := range arr { |
| 188 | + i, j := e.i, e.j |
| 189 | + if !vis1[i] && !vis2[j] { |
| 190 | + vis1[i], vis2[j] = true, true |
| 191 | + ans[i] = j |
| 192 | + } |
| 193 | + } |
| 194 | + return ans |
| 195 | +} |
| 196 | + |
| 197 | +func abs(x int) int { |
| 198 | + if x < 0 { |
| 199 | + return -x |
| 200 | + } |
| 201 | + return x |
| 202 | +} |
77 | 203 | ``` |
78 | 204 |
|
79 | 205 | ### **...** |
|
0 commit comments