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Merge pull request #57 from arindal1/main
Added: 2 JS Codes
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# SVG Path Data Parser
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[Edabit Problem](https://edabit.com/challenge/ysMrKPGby3FXiYtQn)
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A `<path>` element can usually be found inside an `<svg>` element and has an attribute **d** that represents the definition of the outline of a shape.
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A brief summary about this attribute:
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It contains commands (letters) and coordinates (numbers)
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All instructions are expressed as one character (e.g., a moveto is expressed as an **M**).
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Superfluous white space and separators such as commas can be eliminated (e.g., M 10 10 L 20 20 contains unnecessary spaces and could be expressed more compactly as `M10 10L20 20`).
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The command letter can be eliminated on subsequent commands if the same command is used multiple times in a row (e.g., you can drop the second L in `M 10 20 L 20 10 L -10 -20` and use `M 10 20 L 20 10 -10 -20` instead).
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Your job is to build a parser that will convert this string in an array of commands, where each array element is an object with the `command` letter and an array of `parameters`.
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This summary is incomplete but should get you started, for more information please refer to the W3C specification found in the resources tab.
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## Examples
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```javascript
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pathDataParser("") ➞ []
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pathDataParser("M 0 0") ➞ [{command: 'M', parameters: [0, 0]}]
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pathDataParser("M 1 1.5 L 0 1.5 0 0.5 1 0.5 0.5 0 0 0.5 1 1.5 1 0.5 0 1.5" ➞ [
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{command: "M", parameters: [1, 1.5]},
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{command: "L", parameters: [0, 1.5, 0, 0.5, 1, 0.5, 0.5, 0, 0, 0.5, 1, 1.5, 1, 0.5, 0, 1.5]}
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]
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pathDataParser("M 0,1 h 1 v -1 h 1 v 1 h 1 C 2,1 3,3 1.5,3 C 0,3 1,1 0,1 z" ➞ [
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{command: "M", parameters: [0, 1]},
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{command: "h", parameters: [1]},
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{command: "v", parameters: [-1]},
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{command: "h", parameters: [1]},
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{command: "v", parameters: [1]},
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{command: "h", parameters: [1]},
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{command: "C", parameters: [2, 1, 3, 3, 1.5, 3]},
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{command: "C", parameters: [0, 3, 1, 1, 0, 1]},
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{command: "z", parameters: []}
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]
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```
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## Notes:
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- Return an empty array if no commands are found (example #1)
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- The z (or Z) command is the only one without parameters, in this case return an empty array (see last command of example #4)
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- The parameters array contains numbers, not strings, so you'll have to convert them
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- Sometimes numbers can be very compressed to save space, let's look at some examples that might trip you up:
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- Decimal numbers can start with a dot: .4 is the same as 0.4
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- If a negative number comes after another number, the space is optional: 0-4 is equal to 0 -4
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- Multiple decimal numbers in a row can be very tricky, remember that a number CAN NOT have more than 1 dot, so this: 1.2.34 is actually 2 different numbers: 1.2 and 0.34
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- Some examples have commas, some do not, some have multiline strings, some are a single line, remember to take into account all valid cases! Check out the tests tab to find out more.
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## By: arindal1
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***[GitHub](https://github.com/arindal1)***
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function pathDataParser(data) {
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const commands = [];
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let currentCommand = null;
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let currentParams = [];
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let currentParam = '';
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for (let i = 0; i < data.length; i++) {
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const char = data[i];
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if (char === ' ' || char === ',') {
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if (currentParam !== '') {
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currentParams.push(parseFloat(currentParam));
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currentParam = '';
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}
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} else if (/[a-zA-Z]/.test(char)) {
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if (currentCommand !== null) {
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commands.push({ command: currentCommand, parameters: currentParams });
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currentParams = [];
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}
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currentCommand = char;
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} else {
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currentParam += char;
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}
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}
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if (currentCommand !== null) {
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if (currentParam !== '') {
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currentParams.push(parseFloat(currentParam));
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}
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commands.push({ command: currentCommand, parameters: currentParams });
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}
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return commands;
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}
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// Examples
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console.log(pathDataParser(""));
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console.log(pathDataParser("M 0 0"));
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console.log(pathDataParser("M 1 1.5 L 0 1.5 0 0.5 1 0.5 0.5 0 0 0.5 1 1.5 1 0.5 0 1.5"));
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console.log(pathDataParser("M 0,1 h 1 v -1 h 1 v 1 h 1 C 2,1 3,3 1.5,3 C 0,3 1,1 0,1 z"));
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function caesarCipher(str, k) {
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// Helper function to shift a single character by k positions
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function shiftChar(char, k) {
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const isUpperCase = /[A-Z]/.test(char);
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const alphabetSize = 26;
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const baseCharCode = isUpperCase ? 'A'.charCodeAt(0) : 'a'.charCodeAt(0);
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const shiftedCharCode = ((char.charCodeAt(0) - baseCharCode + k) % alphabetSize + alphabetSize) % alphabetSize + baseCharCode;
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return String.fromCharCode(shiftedCharCode);
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}
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let result = '';
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for (let i = 0; i < str.length; i++) {
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const char = str[i];
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if (/[A-Za-z]/.test(char)) {
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result += shiftChar(char, k);
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} else {
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result += char; // Non-alphabetic characters remain unchanged
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}
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}
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return result;
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}
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// Examples
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console.log(caesarCipher("middle-Outz", 2)); // ➞ "okffng-Qwvb"
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console.log(caesarCipher("Always-Look-on-the-Bright-Side-of-Life", 5)); // ➞ "Fqbfdx-Qttp-ts-ymj-Gwnlmy-Xnij-tk-Qnkj"
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console.log(caesarCipher("A friend in need is a friend indeed", 20)); // ➞ "U zlcyhx ch hyyx cm u zlcyhx chxyyx"

‎L-A/0013 Caesar's Cipher/README.md‎

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# Caesar's Cipher
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[Edabit Problem](https://edabit.com/challenge/a33jdGXkaQRtK9ZTs)
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Julius Caesar protected his confidential information by encrypting it using a cipher. Caesar's cipher (check ***Resources*** tab for more info) shifts each letter by a number of letters. If the shift takes you past the end of the alphabet, just rotate back to the front of the alphabet. In the case of a rotation by *3, w, x, y* and *z* would map to *z, a, b* and *c*.
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Create a function that takes a string *s* (text to be encrypted) and an integer *k* (the rotation factor). It should return an encrypted string.
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## Example:
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```javascript
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caesarCipher("middle-Outz", 2) ➞ "okffng-Qwvb"
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// m -> o
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// i -> k
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// d -> f
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// d -> f
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// l -> n
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// e -> g
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// - -
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// O -> Q
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// u -> w
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// t -> v
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// z -> b
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caesarCipher("Always-Look-on-the-Bright-Side-of-Life", 5)
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➞ "Fqbfdx-Qttp-ts-ymj-Gwnlmy-Xnij-tk-Qnkj"
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caesarCipher("A friend in need is a friend indeed", 20)
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➞ "U zlcyhx ch hyyx cm u zlcyhx chxyyx"
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```
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### Notes: All test input will be a valid ASCII string.
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## By: arindal1
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***[GitHub](https://github.com/arindal1)***

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