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This repository was archived by the owner on Dec 19, 2023. It is now read-only.

Commit a5d0180

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Add problem 566
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‎algorithms/566/README.md‎

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## 566. Reshape the Matrix
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In MATLAB, there is a very useful function called 'reshape', which can reshape a matrix into a new one with different size but keep its original data.
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You're given a matrix represented by a two-dimensional array, and two **positive** integers **r** and **c** representing the **row** number and **column** number of the wanted reshaped matrix, respectively.
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The reshaped matrix need to be filled with all the elements of the original matrix in the same **row-traversing** order as they were.
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If the 'reshape' operation with given parameters is possible and legal, output the new reshaped matrix; Otherwise, output the original matrix.
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**Example 1:**
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<pre>
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<b>Input:</b>
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nums =
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[[1,2],
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[3,4]]
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r = 1, c = 4
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<b>Output:</b>
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[[1,2,3,4]]
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<b>Explanation:</b>
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The <b>row-traversing</b> of nums is [1,2,3,4]. The new reshaped matrix is a 1 * 4 matrix, fill
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it row by row by using the previous list.
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</pre>
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**Example 2:**
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<pre>
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<b>Input:</b>
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nums =
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[[1,2],
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[3,4]]
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r = 2, c = 4
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<b>Output:</b>
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[[1,2],
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[3,4]]
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<b>Explanation:</b>
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There is no way to reshape a 2 * 2 matrix to a 2 * 4 matrix. So output the original
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matrix.
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</pre>
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**Note:**
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1. The height and width of the given matrix is in range [1, 100].
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2. The given r and c are all positive.

‎algorithms/566/solution.go‎

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package main
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// Time and space complexity, O(r*c)
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func matrixReshape(nums [][]int, r int, c int) [][]int {
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if len(nums)*len(nums[0]) != r*c {
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return nums
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}
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matrix := make([][]int, r)
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matrix[0] = make([]int, c)
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rr, cc := len(nums), len(nums[0])
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for i, j, ii := 0, 0, 0; ii < rr; ii++ {
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for jj := 0; jj < cc; jj++ {
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if j == c {
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i++
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matrix[i] = make([]int, c)
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j = 0
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}
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matrix[i][j] = nums[ii][jj]
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j++
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}
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}
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return matrix
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}

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