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Commit 14908c2

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Create Maximum Frequency Number
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/*
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You are given an array of integers that contain numbers in random order. Write a program to find and return the number which occurs the maximum times in the given input.
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If two or more elements contend for the maximum frequency, return the element which occurs in the array first.
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Input Format:
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The first line of input contains an integer, that denotes the value of the size of the array. Let us denote it with the symbol N.
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The following line contains N space separated integers, that denote the value of the elements of the array.
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Output Format :
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The first and only line of output contains most frequent element in the given array.
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Constraints:
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0 <= N <= 10^8
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Time Limit: 1 sec
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Sample Input 1 :
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13
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2 12 2 11 12 2 1 2 2 11 12 2 6
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Sample Output 1 :
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2
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Sample Input 2 :
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3
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1 4 5
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Sample Output 2 :
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1
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*/
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import java.util.HashMap;
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public class Solution {
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public static int maxFrequencyNumber(int[] arr){
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/* Your class should be named Solution
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* Don't write main().
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* Don't read input, it is passed as function argument.
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* Return output and don't print it.
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* Taking input and printing output is handled automatically.
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*/
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HashMap<Integer,Integer> countMap = new HashMap<>();
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for (int i=0;i<arr.length;i++)
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{
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int ele=arr[i];
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if (countMap.containsKey(ele))
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{
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countMap.put(ele,countMap.get(ele)+1);
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}
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else
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{
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countMap.put(ele,1);
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}
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}
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int maxCount = Integer.MIN_VALUE, maxEle = arr[0];
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for (int i=0;i<arr.length;i++)
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{
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if (countMap.get(arr[i])>maxCount)
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{
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maxCount=countMap.get(arr[i]);
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maxEle=arr[i];
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}
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}
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return maxEle;
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}
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}

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