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SSA Transform useless phis on exit block #20

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@dibyendumajumdar

Description

This test case:

func foo(x: Int, y: Int)->Int {
 var sum: Int
 
 if (x >= y)
 return 0
 
 sum = 0;
 while (x < y) {
 if (x / 2 * 2 == x) {
 sum = sum + 1
 }
 x = x + 1
 }
 return sum
}

Generates:

After SSA
=========
L0:
 arg x_0
 arg y_0
 %t3_0 = x_0>=y_0
 if %t3_0 goto L2 else goto L3
L2:
 ret 0
 goto L1
L1:
 sum_4 = phi(sum_1, sum_1)
 x_3 = phi(x_1, x_1)
L3:
 sum_0 = 0
 goto L4
L4:
 sum_1 = phi(sum_0, sum_3)
 x_1 = phi(x_0, x_2)
 %t4_0 = x_1<y_0
 if %t4_0 goto L5 else goto L6
L5:
 %t5_0 = x_1/2
 %t6_0 = %t5_0*2
 %t7_0 = %t6_0==x_1
 if %t7_0 goto L7 else goto L8
L7:
 %t8_0 = sum_1+1
 sum_2 = %t8_0
 goto L8
L8:
 sum_3 = phi(sum_1, sum_2)
 %t9_0 = x_1+1
 x_2 = %t9_0
 goto L4
L6:
 ret sum_1
 goto L1

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