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Commit 8c98a36

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🌴 Day 9
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‎README.md‎

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## Week 2 🚧
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1. [Binary Search](https://leetcode.com/explore/challenge/card/october-leetcoding-challenge/560/week-2-october-8th-october-14th/3488/) ➡️ [CPP Solution](Week2/search.cpp)
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2. [Serialize and Deserialize BST](https://leetcode.com/explore/challenge/card/october-leetcoding-challenge/560/week-2-october-8th-october-14th/3489/) ➡️ [CPP Solution](Week2/Codec.cpp)
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## Week 3 🚧
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‎Week2/Codec.cpp‎

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/**
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* Definition for a binary tree node.
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* struct TreeNode {
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* int val;
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* TreeNode *left;
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* TreeNode *right;
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* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
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* };
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*/
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class Codec {
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private:
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char delimiter = ' ';
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// PreOrder
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void dfs(TreeNode* root, string& s) {
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if(root == NULL) return;
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s.append(to_string(root->val) + delimiter);
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dfs(root->left, s);
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dfs(root->right, s);
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}
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vector<int> stringToVector(string s) {
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vector<int> res;
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int n = s.size();
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int i = 0;
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string tmp = "";
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while(i < n) {
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while(i < n && s[i] != delimiter) {
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tmp += s[i];
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i++;
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}
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res.push_back(stoi(tmp));
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tmp.erase();
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i++;
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}
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return res;
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}
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TreeNode* createBST(vector<int> nums, int start, int end) {
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if(start > end) return NULL;
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TreeNode* root = new TreeNode(nums[start]);
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int index;
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for(index = start; index <= end; ++index) {
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if(nums[index] > nums[start]) break;
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}
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root->left = createBST(nums, start + 1, index - 1);
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root->right = createBST(nums, index, end);
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return root;
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}
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public:
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// Encodes a tree to a single string.
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string serialize(TreeNode* root) {
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if(root == NULL) return "";
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string s = "";
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dfs(root, s);
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return s;
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}
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// Decodes your encoded data to tree.
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TreeNode* deserialize(string data) {
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if(data == "") return NULL;
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vector<int> nums = stringToVector(data);
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return createBST(nums, 0, nums.size() - 1);
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}
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};
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// Your Codec object will be instantiated and called as such:
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// Codec* ser = new Codec();
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// Codec* deser = new Codec();
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// string tree = ser->serialize(root);
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// TreeNode* ans = deser->deserialize(tree);
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// return ans;

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