Hi,
I'm doing a data step scenario to show telephone_uid (tel_number in data step code) with more than 1 unique full_name.
Screenshot 2022年03月29日 234340.jpg Here is my data step code:
Screenshot 2022年03月29日 234620.jpg
I need an advice on how to correct my code to show only those tel_number with more than 1 full_name associated on it.
Thank you.
Regards,
Adrian
Below code should work but is untested because you didn't provide sample data in a usable format.
proc sort
data=&input_dataset(keep=tel_number full_name)
out=intermediate
nodupkey;
by tel_number full_name;
run;
data &output_dataset;
set intermediate;
by tel_number;
if first.tel_number then name_count=1;
else name_count+1;
if last.tel_number and name_count>1 then
do;
&message=catx(' ','Telephone : ',tel_number,'Suspicious.... to', name_count,'people...');
....
output;
end;
run;
For future questions please post your data and code as text and not as screenshots. Use icons
[画像:Patrick_0-1648583285463.png]
to do so.
Would you have been happy if I'd posted my reply as picture?
Below code should work but is untested because you didn't provide sample data in a usable format.
proc sort
data=&input_dataset(keep=tel_number full_name)
out=intermediate
nodupkey;
by tel_number full_name;
run;
data &output_dataset;
set intermediate;
by tel_number;
if first.tel_number then name_count=1;
else name_count+1;
if last.tel_number and name_count>1 then
do;
&message=catx(' ','Telephone : ',tel_number,'Suspicious.... to', name_count,'people...');
....
output;
end;
run;
For future questions please post your data and code as text and not as screenshots. Use icons
[画像:Patrick_0-1648583285463.png]
to do so.
Would you have been happy if I'd posted my reply as picture?
sasinnovate.png
April 27 – 30 | Gaylord Texan | Grapevine, Texas
Walk in ready to learn. Walk out ready to deliver. This is the data and AI conference you can't afford to miss.
Register now and lock in 2025 pricing—just 495ドル!
Still thinking about your presentation idea? The submission deadline has been extended to Friday, Nov. 14, at 11:59 p.m. ET.