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Zsh, 68 bytes

-3 bytes thanks to @pxeger

for ((;#1;)){s=
for y ({A..Z})s+=${(Ml[1])1[1]%$y}&&1=${1#$y}
<<<$s}

(削除) Try it online! (削除ここまで) Try it online!

Append to $s a matched letter, padded to one character, in one statement, then removing the letter if it matches from the front of 1ドル.