Add two numbers

Question

Input: Two integers. Preferably decimal integers, but other forms of numbers can be used. These can be given to the code in standard input, as arguments to the program or function, or as a list.

Output: Their sum. Use the same format for output integers as input integers. For example, the input 5 16 would lead to the output 21.

Restrictions: No standard loopholes please. This is code-golf, answer in lowest amount of bytes wins.

Notes: This should be fairly trivial, however I'm interested to see how it can be implemented. The answer can be a complete program or a function, but please identify which one it is.

Test cases:

1 2 -> 3
14 15 -> 29
7 9 -> 16
-1 8 -> 7
8 -9 -> -1
-8 -9 -> -17

Or as CSV:

a,b,c
1,2,3
14,15,29
7,9,16
-1,8,7
8,-9,-1
-8,-9,-17

Leaderboard

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• Dennis: This is quite trivial, but not really simpler than, e.g., the Hello World catalog. Given that the ability to add integers is one of our two requirements for programming languages, I'd say it's worthwhile to have if properly specified.
• FinW: Can the answer take input with preceding zeros as default? e.g. 5 16 is inputted as 005 016
• anna328p: @FinW Sure. As long as they don't get interpreted as octal.

Answer 1

Visual Basic.NET, 39 bytes

Function F(x,y)
Return x+y
End Function

Without Option Strict On (which you definitely want for any real coding), no data types are required (As type).

With Option Strict On:

Function F(x As Integer,y As Integer) As Integer
Return x+y
End Function

Answer 2

Decimal, 12 bytes

81D81D41D301

Explanation:

81D ; builtin - read INT from STDIN, push to stack
81D ; builtin - read INT from STDIN, push to stack
41D ; math +, pop values used, push result
301 ; print from stack to STDOUT

• MD XF: TIO link coming as soon as the latest Decimal version is pulled to TIO.

Answer 3

Standard ML (MLton), 3 bytes

op+

Try it online!

An anonymous function that behaves as the + operator, on a tuple of two integers.

Answer 4

Check, 2 bytes

+p

Input is from command-line args.

+ adds the two numbers, and p prints it.

Answer 5

SQL, 19 bytes

SELECT SUM(a)FROM t

Our rules allow SQL to input via a pre-existing named table (in this case table t with INT field a), so just SUM it up and output the results.

Works for however many rows are in the input table.

Answer 6

Ruby, 17 bytes

def f(i,j)i+j;end

Functions in Ruby return the last evaluated expression.

• manatwork: Anonymous Proc is also acceptable: ->i,j{i+j}. (You call it like ->i,j{i+j}[3,4].)

Answer 7

Element, 4 bytes

__+`

Explanation:

_ input to stack
_ input to stack
+ add top two stack elements
` pop to output

https://tio.run/##S81JzU3NK/n/Pz5eO@H/fyMFLmMA

Answer 8

Excel VBA, 8 Bytes

Anonymous VBE immediate window function that takes arguments from the range [A1:B1] and outputs their sum to the VBE immediate window

?[A1+B1]

Answer 9

MS Excel / Google Sheets, 6 Bytes

Anonymous Worksheet function that takes input from the range A1:B1 and outputs their sum to the worksheet cell that holds this formula.

=A1+B1

Answer 10

DUP, 37 bytes

[0[`32ドル-][10円*(48ドル-)+\%]#%]⇒II(I)+.

Both integers have to be space terminated (ASCII 32)

Explanation, taking example 11+3:

[0[`32ドル-][10円*(48ドル-)+\%]#%]⇒I {I defines an operator that converts space-terminated character strings to integer numbers}
[ ]⇒I {Definition of operator I}
 0 {push 0 on ds (data stack)}
 [cond.][ block ]# {while condition nonzero do block}
 ` {read character from STDIN to ds}
 $ {DUP ds top value}
 32- {push 32 on ds, SUB}
 \ {SWAP topmost ds values}
 10* {push 10 on ds, MUL}
 ( {move ds top value to rs (return stack)}
 $ {DUP}
 48- {push 48, SUB}
 ) {move rs top back to ds}
 + {ADD}
 \% {SWAP, POP}
 % {POP}

I reads in numbers as single characters and converts them to decimal numbers (basically by a base 10 shift left, add loop). I also checks if a terminating space is found, and if that’s the case, exits the read in loop and removes junk from the stack.

Actual program:

I {Read in first integer character by character}
 ( {move ds top to rs}
 I {read in second integer}
 ) {move first integer back from rs to ds}
 + {ADD}
 . {output sum to STDOUT}

Try it out in this online DUP interpreter.

Answer 11

ARBLE, 3 bytes

a+b

Try it online!

Answer 12

Spiral, 6 bytes

0;;+,!

Interpreter

Answer 13

Pyth - 5 Bytes

AQ+GH

A Set variables G and H to the first two elements of
 Q Input;
 Implicitly Print
 G G
 + plus
 H H

• hakr14: s?

Answer 14

SNOBOL4 (CSNOBOL4), 26 bytes

 OUTPUT =INPUT + INPUT
END

Try it online!

Answer 15

Beatnik, 9 bytes

x x kg ja

Try it online!

I/O in codepoint values, so !! -> B, B! -> c. Works with larger numbers on Unicode interpreters.

Answer 16

√ å ı \ ® Ï Ø ¿, 3 bytes

i+o

Try it online!

i+o
i takes input as a flattened list
 + adds
 o outputs

Answer 17

jamal, 22 characters

(12 characters code + 10 characters command line options)

{#+ {a} {b}}

Strictly because the question owner wrote "I'm interested to see how it can be implemented".

Sample run:

bash-4.4$ perl jamal.pl -Da=5 -Db=16 add.jam
21

Answer 18

m4, 19 characters

(9 characters code + 10 characters command line options)

eval(a+b)

Strictly because the question owner wrote "I'm interested to see how it can be implemented".

Sample run:

bash-4.4$ m4 -Da=5 -Db=16 <<< 'eval(a+b)'
21

Try it online!

Answer 19

Flobnar, 4 bytes

&
+@

Try it online!

Answer 20

F# (Mono), 3 bytes

(+)

In F#, the + operator is defined as a function named (+).

The following prints 3 and shows how to pass parameters to this function. To me, this is the clearest way to see that (+) is actually a function.

printf "%d" ((+) 1 2)

Try it online!

Answer 21

PHP, 20 bytes

Assuming the script will always have 2 arguments

<?php
$argv[0] = 10;
$argv[1] = 23;
?>

<?=array_sum($argv); // Well, all the arguments are stored on the $argv array
 // the array can just be added

Try it online!

Answer 22

RTFM, 24 bytes

Btw, it's my first answer on PPCG.

041 x 041 y 070 010[x,y]

• Wheat Wizard: Welcome to the site!

Answer 23

Duocentehexaquinquagesimal, 5 bytes

3Σa;â

Try it online!

Answer 24

Ly, 2 bytes

+u

Try it online!

The + command adds the top two entries on the stack. And if there's nothing on the stack, it will read from STDIN. Then the u prints the results as a number.

Answer 25

Neutrino, 1 byte

+

Try it online!

Takes arguments on the command line. The language can't do very much :P

Answer 26

Kotlin, 10 bytes

var sum:(Int, Int) -> Int= 

{a,b->a+b}

Try it online!

Answer 27

Halfwit, 0.5 bytes

+

Try It Online!

Pretty obvious.

Answer 28

RubyGolf, 15 bytes

p gets.i+gets.i

code is so short it hit the character limit. ugh.

New language created by me, interpreter going up soon.

Answer 29

awk, 9-bytes

($_+=2ドル)_

echo "${test_data}\n-2 2" | gtee >( gcat -n >&2;) | 
awk '($_+=2ドル)_' 

• no idea why slipping (......)_ works, but somehow it does. my best guess is that it's forcing a string concat with an empty string, thus allowing the zero to print properly.

.

 1 1 2
 2 14 15
 3 7 9
 4 -1 8
 5 8 -9
 6 -8 -9
 7 -2 2
3
29
16
7
-1
-17
0

• naffetS: using a number instead of _ works too, so it's not coerced to an empty string. i think it's just the normal truthy condition: unix.stackexchange.com/a/63897
• RARE Kpop Manifesto: it's not being coerced to an empty string, but rather, with an empty string. maybe very minor diff grammatically, but totally opposite effects in awk. Also, setting a } 1' means empty rows get printed too, if that's the desired effect, while this (. . .)_ would print rows with numeric zero but skip actually empty rows. it's extremely subtle difference .... almost feel like i'm splitting the proton here.

Answer 30

Swift, (削除) 25 (削除ここまで) 20 bytes

var t:(_,_)->Int=(+)