C, (削除) 77 (削除ここまで) (削除) 74 (削除ここまで) 71 bytes
Basically the same as the Python answer inspired by LeakyNun Python answer inspired by LeakyNun, Thanks to owacoder for puts
:
f(i,j){for(i=0;++i<27;puts(""))for(j=13;--j;printf("%c%c",i+64,i%26+65));}
Usage:
f();
(削除) While mathematically Using a count up loop for (26-n)%26 == (-n)%26, this is not true for C, otherwise these two bytes can be shaved off. (削除ここまで)i resolves the problem
C, (削除) 77 (削除ここまで) (削除) 74 (削除ここまで) 71 bytes
Basically the same as the Python answer inspired by LeakyNun, Thanks to owacoder for puts
:
f(i,j){for(i=0;++i<27;puts(""))for(j=13;--j;printf("%c%c",i+64,i%26+65));}
Usage:
f();
(削除) While mathematically Using a count up loop for (26-n)%26 == (-n)%26, this is not true for C, otherwise these two bytes can be shaved off. (削除ここまで)i resolves the problem
C, (削除) 77 (削除ここまで) (削除) 74 (削除ここまで) 71 bytes
Basically the same as the Python answer inspired by LeakyNun, Thanks to owacoder for puts
:
f(i,j){for(i=0;++i<27;puts(""))for(j=13;--j;printf("%c%c",i+64,i%26+65));}
Usage:
f();
(削除) While mathematically Using a count up loop for (26-n)%26 == (-n)%26, this is not true for C, otherwise these two bytes can be shaved off. (削除ここまで)i resolves the problem
C, (削除) 77 (削除ここまで) 74(削除) 74 (削除ここまで) 71 bytes
Basically the same as the Python answer inspired by LeakyNun , Thanks to owacoder for puts:
f(i,j){for(i=0;++i<27;printfi=0;++i<27;puts("\n"""))for(j=13;--j;printf("%c%c",i+64,i%26+65));}
Usage:
f();
(削除) While mathematically Using a count up loop for (26-n)%26 == (-n)%26, this is not true for C, otherwise these two bytes can be shaved off. (削除ここまで)i resolves the problem
C, (削除) 77 (削除ここまで) 74 bytes
Basically the same as the Python answer inspired by LeakyNun:
f(i,j){for(i=0;++i<27;printf("\n"))for(j=13;--j;printf("%c%c",i+64,i%26+65));}
Usage:
f();
(削除) While mathematically Using a count up loop for (26-n)%26 == (-n)%26, this is not true for C, otherwise these two bytes can be shaved off. (削除ここまで)i resolves the problem
C, (削除) 77 (削除ここまで) (削除) 74 (削除ここまで) 71 bytes
Basically the same as the Python answer inspired by LeakyNun , Thanks to owacoder for puts:
f(i,j){for(i=0;++i<27;puts(""))for(j=13;--j;printf("%c%c",i+64,i%26+65));}
Usage:
f();
(削除) While mathematically Using a count up loop for (26-n)%26 == (-n)%26, this is not true for C, otherwise these two bytes can be shaved off. (削除ここまで)i resolves the problem
C, 77(削除) 77 (削除ここまで) 74 bytes
Basically the same as the Python answer inspired by LeakyNun:
f(i,j){for(i=26;--i;printfi=0;++i<27;printf("\n"))for(j=13;--j;printf("%c%c",90-ii+64,(26-i)%26+65i%26+65));}
Usage:
f();
While mathematically (削除) While mathematically Using a count up loop for (26-n)%26 == (-n)%26, this is not true for C, otherwise these two bytes can be shaved off. (削除ここまで)(26-n)%26 == (-n)%26i, this is not true for C, otherwise these two bytes can be shaved off. resolves the problem
C, 77 bytes
Basically the same as the Python answer inspired by LeakyNun:
f(i,j){for(i=26;--i;printf("\n"))for(j=13;--j;printf("%c%c",90-i,(26-i)%26+65));}
Usage:
f();
While mathematically (26-n)%26 == (-n)%26, this is not true for C, otherwise these two bytes can be shaved off.
C, (削除) 77 (削除ここまで) 74 bytes
Basically the same as the Python answer inspired by LeakyNun:
f(i,j){for(i=0;++i<27;printf("\n"))for(j=13;--j;printf("%c%c",i+64,i%26+65));}
Usage:
f();
(削除) While mathematically Using a count up loop for (26-n)%26 == (-n)%26, this is not true for C, otherwise these two bytes can be shaved off. (削除ここまで)i resolves the problem