Timeline for Prove that a Number is Algebraic
Current License: CC BY-SA 4.0
18 events
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| Jun 11, 2024 at 16:59 | history | edited | mbomb007 | CC BY-SA 4.0 |
edited tags
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| Jun 17, 2020 at 9:04 | history | edited | Community Bot |
Commonmark migration
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| Apr 13, 2017 at 12:19 | history | edited | Community Bot |
replaced http://math.stackexchange.com/ with https://math.stackexchange.com/
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| Oct 28, 2016 at 14:03 | vote | accept | mbomb007 | ||
| Jun 22, 2016 at 20:04 | comment | added | mbomb007 | @AndersKaseorg Multiplying by negatives is fine. Not the others. | |
| Jun 22, 2016 at 19:15 | comment | added | Anders Kaseorg |
@mbomb007 Do you consider +-3, ++3, --3, -+3, *-3, *+3 to be valid output terms (adding/subtracting/multiplying the integer −3 or +3)?
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| Jun 22, 2016 at 18:49 | comment | added | Anders Kaseorg |
@mbomb007 Division is not required. You can always move divisions to the end (/a +b ↦ +(a*b) /a, /a -b ↦ -(a*b) /a, /a *b ↦ *b /a, /a *x ↦ *x /a) and then delete them.
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| Jun 22, 2016 at 15:29 | answer | added | LLlAMnYP | timeline score: 1 | |
| Jun 22, 2016 at 14:31 | history | edited | mbomb007 | CC BY-SA 3.0 |
added 22 characters in body
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| Jun 21, 2016 at 22:02 | history | tweeted | twitter.com/StackCodeGolf/status/745376381073227777 | ||
| Jun 21, 2016 at 21:42 | answer | added | Anders Kaseorg | timeline score: 4 | |
| Jun 21, 2016 at 21:09 | history | edited | mbomb007 | CC BY-SA 3.0 |
deleted 34 characters in body
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| Jun 21, 2016 at 20:57 | comment | added | mbomb007 |
It's a solution to the equation x^4-10*x^2+1. See WolframAlpha
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| Jun 21, 2016 at 20:52 | comment | added | Mario Ishac | @mbomb007 Whoops, my apologies, didn't catch that in the OP. | |
| Jun 21, 2016 at 20:48 | comment | added | Mario Ishac | How is √2+√3 algebraic? If you multiply the number by itself you get 5 + 2√6... unless I am missing something you can never force out the radical. | |
| Jun 21, 2016 at 20:47 | comment | added | mbomb007 | @TimmyD The answer needs to be exact, such that I could perform the operations and get zero. View the examples provided. There is no floating point arithmetic. | |
| Jun 21, 2016 at 20:44 | comment | added | AdmBorkBork |
How close to 0 do the results need to be? Given rounding errors and float precision, I could easily see problematic situations ...
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| Jun 21, 2016 at 20:25 | history | asked | mbomb007 | CC BY-SA 3.0 |