TI-BASIC, 24(削除) 24 (削除ここまで) 22
-1+int(11fPart(11^Ans.0954191038120954191904
This encodes the possible outputs in a lookup table stored as a base-11 floating point number; the (N+1)th base-11 digit after the decimal point is extracted from the table to get the value of the inverted digit. In base 11 the number is .106003A097, and the digits of this minusless one are exactly 0,-1,5,-1,-1,2,9,-1,8,6.
Also 24 bytes is base-10 encoding using edc65's trick of subtracting one only whenin the input iscase of 6. The leads to this 24-byte solution, where 10^( is a single one-byte token displayed as "10^:
-(Ans≠6)+int(10fPart(.106003909710^(Ans
The string approach is 29 bytes:
-(Ans≠6)+expr(inString("1060039097",Ans+1,1
The array approach (".which Ypnpyn also took) is 30 bytes, assuming the number is stored in X:
{1,0,6,0,0,3,10,0,9,7}-1:Ans(X+1
-(Ans≠6)+int(10fPart(.106003909710^(X 24 -> 22: Removed two extra digits of precision in the magic constant.
TI-BASIC, 24
-1+int(11fPart(11^Ans.095419103812
This encodes the possible outputs in a lookup table stored as a base-11 floating point number; the (N+1)th base-11 digit after the decimal point is extracted from the table to get the value of the inverted digit. In base 11 the number is .106003A097, and the digits of this minus one are exactly 0,-1,5,-1,-1,2,9,-1,8,6.
Also 24 bytes is base-10 encoding using edc65's trick of subtracting one only when the input is 6. The 10^( is a single token displayed as "10^(".
-(Ans≠6)+int(10fPart(.106003909710^(X
TI-BASIC, (削除) 24 (削除ここまで) 22
-1+int(11fPart(11^Ans.0954191904
This encodes the possible outputs in a lookup table stored as a base-11 floating point number; the (N+1)th base-11 digit after the decimal point is extracted from the table to get the value of the inverted digit. In base 11 the number is .106003A097, and the digits of this less one are exactly 0,-1,5,-1,-1,2,9,-1,8,6.
edc65's trick of subtracting one in the case of 6 leads to this 24-byte solution, where 10^( is a single one-byte token:
-(Ans≠6)+int(10fPart(.106003909710^(Ans
The string approach is 29 bytes:
-(Ans≠6)+expr(inString("1060039097",Ans+1,1
The array approach (which Ypnpyn also took) is 30 bytes, assuming the number is stored in X:
{1,0,6,0,0,3,10,0,9,7}-1:Ans(X+1
24 -> 22: Removed two extra digits of precision in the magic constant.
TI-BASIC, 24
-1+int(11fPart(11^Ans.095419103812
This encodes the possible outputs in a lookup table stored as a base-11 floating point number; the (N+1)th base-11 digit after the decimal point is extracted from the table to get the value of the inverted digit. In base 11 the number is .106003A097, and the digits of this minus one are exactly 0,-1,5,-1,-1,2,9,-1,8,6.
I have not been able to exploit any order inAlso 24 bytes is base-10 encoding using edc65's trick of subtracting one only when the datainput is 6. The 10^( is a single token displayed as "10^(".
-(Ans≠6)+int(10fPart(.106003909710^(X
TI-BASIC, 24
-1+int(11fPart(11^Ans.095419103812
This encodes the possible outputs in a lookup table stored as a base-11 floating point number; the (N+1)th base-11 digit after the decimal point is extracted from the table to get the value of the inverted digit. In base 11 the number is .106003A097, and the digits of this minus one are exactly 0,-1,5,-1,-1,2,9,-1,8,6.
I have not been able to exploit any order in the data.
TI-BASIC, 24
-1+int(11fPart(11^Ans.095419103812
This encodes the possible outputs in a lookup table stored as a base-11 floating point number; the (N+1)th base-11 digit after the decimal point is extracted from the table to get the value of the inverted digit. In base 11 the number is .106003A097, and the digits of this minus one are exactly 0,-1,5,-1,-1,2,9,-1,8,6.
Also 24 bytes is base-10 encoding using edc65's trick of subtracting one only when the input is 6. The 10^( is a single token displayed as "10^(".
-(Ans≠6)+int(10fPart(.106003909710^(X
TI-BASIC, 24
-1+int(11fPart(11^Ans.095419103812
This encodes the possible outputs in a lookup table stored as a base-11 floating point number; the (N+1)th base-11 digit after the decimal point is extracted from the table to get the value of the inverted digit. In base 11 the number is .106003A097, and the digits of this minus one are exactly 0,-1,5,-1,-1,2,9,-1,8,6.
I have not been able to exploit any order in the data.