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Replace 0s In a String With Their Consecutive Counts

Challenge

Given a string of any length which contains only digits from 0 to 9, replace each consecutive run of the digit 0 with its length.

Test Cases

1234500362000440 → 1234523623441
123450036200044 → 123452362344
000000000000 → 12
0123456789 → 1123456789
1234567890 → 1234567891
123456789 → 123456789
010203004050 → 11121324151

Note

The shortest answer in bytes wins as per code-golf rules

Answer*

If this is an answer to a challenge…

…Be sure to follow the challenge specification. However, please refrain from exploiting obvious loopholes. Answers abusing any of the standard loopholes are considered invalid. If you think a specification is unclear or underspecified, comment on the question instead.
…Try to optimize your score. For instance, answers to code-golf challenges should attempt to be as short as possible. You can always include a readable version of the code in addition to the competitive one. Explanations of your answer make it more interesting to read and are very much encouraged.
…Include a short header which indicates the language(s) of your code and its score, as defined by the challenge.

More generally…

…Please make sure to answer the question and provide sufficient detail.
…Avoid asking for help, clarification or responding to other answers (use comments instead).

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\$\begingroup\$ if the string ends in 0s, it just removes them: Try it online! \$\endgroup\$

naffetS
– naffetS

2022年12月27日 00:29:37 +00:00
Commented Dec 27, 2022 at 0:29
\$\begingroup\$ here's 59 based on what you curerntly have though, to give you a good base: Try it online! \$\endgroup\$

naffetS
– naffetS

2022年12月27日 00:46:15 +00:00
Commented Dec 27, 2022 at 0:46
\$\begingroup\$ no it doesn't fix it, i just golfed your current code down. Try it online! that should end in a 3 \$\endgroup\$

naffetS
– naffetS

2022年12月27日 00:52:37 +00:00
Commented Dec 27, 2022 at 0:52
\$\begingroup\$ @Steffan fixed, thanks \$\endgroup\$

James Risner
– James Risner

2022年12月31日 21:02:56 +00:00
Commented Dec 31, 2022 at 21:02

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