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Replace 0s In a String With Their Consecutive Counts

Challenge

Given a string of any length which contains only digits from 0 to 9, replace each consecutive run of the digit 0 with its length.

Test Cases

1234500362000440 → 1234523623441
123450036200044 → 123452362344
000000000000 → 12
0123456789 → 1123456789
1234567890 → 1234567891
123456789 → 123456789
010203004050 → 11121324151

Note

The shortest answer in bytes wins as per code-golf rules

Answer*

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…Try to optimize your score. For instance, answers to code-golf challenges should attempt to be as short as possible. You can always include a readable version of the code in addition to the competitive one. Explanations of your answer make it more interesting to read and are very much encouraged.
…Include a short header which indicates the language(s) of your code and its score, as defined by the challenge.

More generally…

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\$\begingroup\$ Here's a TIO link for you. The % isn't necessary because the input "contains only digits from 0 to 9" and therefore contains no newlines. However, if your language is Vim and not V, I think you have to count the Enter keypress after the replace command (otherwise, the replacement doesn't happen), so that makes it 28 bytes. If you want to call it V instead of Vim, you can skip the newline and claim 27 bytes. \$\endgroup\$

DLosc
– DLosc

2022年12月22日 18:22:41 +00:00
Commented Dec 22, 2022 at 18:22
\$\begingroup\$ Thanks @DLosc, edited. \$\endgroup\$

D. Ben Knoble
– D. Ben Knoble

2022年12月22日 23:13:25 +00:00
Commented Dec 22, 2022 at 23:13

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