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c%16+13%10+48, as precedence makes it equivalent to(c%16)+51, but I'm not sure what exactly the precedence you intended was \$\endgroup\$nin the generated code would help, as it operates on the whole buffer, and the generated code relies on preserving what it's already build. \$\endgroup\$len - indwithlen - ind - (len - ind) % 47. (Also, using arrays of character codes is very fiddly; generator code is much simpler if you use strings instead.) \$\endgroup\$