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MarcMush
  • 6.9k
  • 15
  • 18

Julia, 17(削除) 17 (削除ここまで) 16 bytes

F(!,+,a,b)=!a+!b

Try it online!

Previous answer, 17 bytes

g*f*x=g(f.(x)...)

expects g*f*(a,b)

also works with more than 2 arguments

Try it online!

Julia, 17 bytes

g*f*x=g(f.(x)...)

expects g*f*(a,b)

also works with more than 2 arguments

Try it online!

Julia, (削除) 17 (削除ここまで) 16 bytes

F(!,+,a,b)=!a+!b

Try it online!

Previous answer, 17 bytes

g*f*x=g(f.(x)...)

Try it online!

Source Link
MarcMush
  • 6.9k
  • 15
  • 18

Julia, 17 bytes

g*f*x=g(f.(x)...)

expects g*f*(a,b)

also works with more than 2 arguments

Try it online!

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