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added 269 characters in body

edited Mar 1, 2021 at 14:54

edited Mar 1, 2021 at 14:54

Lua (75Lua , 75 bytes)

function C(x)z=0 while x>1 do x=({x//2,3*x+1})[x%2+1]z=z+1 end return z end

function C(x)z=0 while x>1 do x=({x//2,3*x+1})[x%2+1]z=z+1 end return z end

function C(x)z=0 while x>1 do x=({x//2,3*x+1})[x%2+1]z=z+1 end return z end

answered Mar 1, 2021 at 14:28

answered Mar 1, 2021 at 14:28

function C(x)z=0 while x>1 do x=({x//2,3*x+1})[x%2+1]z=z+1 end return z end