Timeline for Is this a valid Shakashaka solution?

11 events

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Jun 23, 2020 at 17:37	comment	added	The Fifth Marshal		You appear to have gotten my technique to work, anyway, though, with some of your own modifications, so I at least provided an idea. (I'm deleting my own comments as they get responded to so the comment section doesn't get too cluttered)
Jun 23, 2020 at 17:34	comment	added	fireflame241		@pppery Yep, that's the power of using all the testcases. The problem with the 473-byte code was that it modified `a` within the function, though it did deal with `v` and `n` properly
Jun 23, 2020 at 17:30	history	edited	fireflame241	CC BY-SA 4.0	-a few bytes
Jun 23, 2020 at 17:02	history	edited	fireflame241	CC BY-SA 4.0	-55 bytes
Jun 23, 2020 at 8:03	comment	added	ovs		All combined: Try it online!.
Jun 23, 2020 at 7:59	comment	added	ovs		And replace the last part of `F` with `[(c>>a&1)(a+y)(3-a+x)and F(x+a%2*(2-a),y+(a-1&~a),1<<(a^2))for a in(0,1,2,3)]` for another -4 bytes. Then you can move the check for `x` and `y` to the front.
Jun 23, 2020 at 6:23	comment	added	ovs		You can wrap the entire `F` function in `try/except` and return by throwing an error: Try it online!.
Jun 23, 2020 at 0:57	history	edited	fireflame241	CC BY-SA 4.0	-28 bytes
Jun 22, 2020 at 23:03	history	edited	fireflame241	CC BY-SA 4.0	-113 bytes
Jun 22, 2020 at 22:48	history	edited	fireflame241	CC BY-SA 4.0	Add commented, ungolfed
Jun 22, 2020 at 21:51	history	answered	fireflame241	CC BY-SA 4.0