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Rev

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Unfurl a string

Given a square string, produce all the output for the string at every stage of unfurling.

The string must unfurl in a clockwise direction one quarter turn at a time.

Examples

Input:

Output:

Note: I'll also accept the input duplicated for this particular test case only if this helps reduce your byte count.

Input:

DC
AB

Output:

DC
AB
 D
ABC
ABCD

Input:

GFE
HID
ABC

Output:

GFE
HID
ABC
 HG
 IF
ABCDE
 IH
ABCDEFG
 I
ABCDEFGH
ABCDEFGHI

Input:

JIHG
KPOF
LMNE
ABCD

Output:

JIHG
KPOF
LMNE
ABCD
 LKJ
 MPI
 NOH
ABCDEFG
 NML
 OPK
ABCDEFGHIJ
 ON
 PM
ABCDEFGHIJKL
 PO
ABCDEFGHIJKLMN
 P
ABCDEFGHIJKLMNO
ABCDEFGHIJKLMNOP

Rules

This is code-golf so the shortest code in bytes wins.

Any reasonable format can be used for I/O assuming it is consistent.
Spaces must be used to pad the top lines of the output.
Must be able to handle input of all printable characters (including space: \x20-\x7e):

 !"#$%&'()*+,-./0123456789:;?@ABCDEFGHIJKLMNOPQRSTUVWXYZ[\]^_`abcdefghijklmnopqrstuvwxyz{|}~

Leading/trailing whitespace is allowed.
You can assume the string will always be a square.
All standard loopholes are forbidden.

Inspiration: Write a square program that outputs the number of times it has been "unrolled".

Answer*

# [Python 2], <s>209 207 205 203 202 201 200</s> 196 bytes

-4 bytes thanks to [@Quelklef](https://codegolf.stackexchange.com/users/43266/quelklef)!



 s=input();l=len;k=''.join;exec"print s;s=[x for x in[' '*l(s[0])+k(x[:-1]for x in s[-2::-1])[t::l(s[0])-1]for t in range(l(s[0]))][:-1]+[s[-1]+k(x[-1]for x in s)[-2::-1]]if x.strip()];"*(2*l(s)-1)

[Try it online!][TIO-j6pjmfkc]

[Python 2]: https://docs.python.org/2/
[TIO-j6pjmfkc]: https://tio.run/##VY7JDoIwFEV/5aUbWhSiLNt04TwP@6YLY0ArpDS0JvXrkRpYuLrJu@eePPNxz1pnbWu50ubtMGEVr3LNSh5F6atWmuU@vyPTKO3AMsuFh6JuwIPSIoIorrAVE0lGJfaCJlM5lGBFktFwIcJR2mM94ALQ3PQjx31B5G89Et2si2D7k5HBJlUBPrWuUQYTyVCMs/BDZyZtK9B@t92gMaDD9bIOeTydVyFn88USyS8 "Python 2 – Try It Online"

# [Python 2], <s>219 217 215 213 212 211</s> 207 bytes



 s=input();l=len;k=''.join;exec"print'\\n'.join(s);s=[x for x in[' '*l(s[0])+k(x[:-1]for x in s[-2::-1])[t::l(s[0])-1]for t in range(l(s[0]))][:-1]+[s[-1]+k(x[-1]for x in s)[-2::-1]]if x.strip()];"*(2*l(s)-1)

[Try it online!][TIO-j6pjnq4b]

[Python 2]: https://docs.python.org/2/
[TIO-j6pjnq4b]: https://tio.run/##VY45D4MgAIX/CmEBtJrWUeLQ@z52ZGgabakGDdCE/noqrQ6dXvKOL699m0cjE@d0JmT7MpjQOqsLSasMofjZCEkLW9xgq4Q0KM/lz8SaUJ0xC8pGAQuEZAigoMaajTkJK2xZGk34EALNoiT1DmEmTftaXzC@oK7yXuA@IPy7Dlk368TT/mBkoHFRAhtro0SLCacwwIn/0JGJcwzutps1HAG4v5xXXg/H09LrdDZfQP4B "Python 2 – Try It Online"

The first one outputs as a list of Strings, the second one outputs as ASCII-art.

If this is an answer to a challenge…

…Be sure to follow the challenge specification. However, please refrain from exploiting obvious loopholes. Answers abusing any of the standard loopholes are considered invalid. If you think a specification is unclear or underspecified, comment on the question instead.
…Try to optimize your score. For instance, answers to code-golf challenges should attempt to be as short as possible. You can always include a readable version of the code in addition to the competitive one. Explanations of your answer make it more interesting to read and are very much encouraged.
…Include a short header which indicates the language(s) of your code and its score, as defined by the challenge.

More generally…

…Please make sure to answer the question and provide sufficient detail.
…Avoid asking for help, clarification or responding to other answers (use comments instead).

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Edit Summary*

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\$\begingroup\$ I think [::-1][1:] can be [-2::-1], like in Lynn's answer. \$\endgroup\$

Quelklef
– Quelklef

2017年08月23日 21:38:44 +00:00
Commented Aug 23, 2017 at 21:38
\$\begingroup\$ @Quelklef Thanks a lot! \$\endgroup\$

Mr. Xcoder
– Mr. Xcoder

2017年08月23日 21:40:38 +00:00
Commented Aug 23, 2017 at 21:40

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