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Commonmark migration

edited Jun 17, 2020 at 9:04

edited Jun 17, 2020 at 9:04

1

#cQuents , 5 bytes

cQuents , 5 bytes

#3::$

Outputs 1,2,3. This works because of the mode, ::. :: prints the sequence up to n, which in this case is hardcoded in as 3. $ prints the current index - it could be replaced with any single digit. So, the interpreter prints out the first three items in the $ sequence, separated by the default delimiter, ,.

#cQuents , 5 bytes

#3::$

Outputs 1,2,3. This works because of the mode, ::. :: prints the sequence up to n, which in this case is hardcoded in as 3. $ prints the current index - it could be replaced with any single digit. So, the interpreter prints out the first three items in the $ sequence, separated by the default delimiter, ,.

cQuents , 5 bytes

#3::$

Outputs 1,2,3. This works because of the mode, ::. :: prints the sequence up to n, which in this case is hardcoded in as 3. $ prints the current index - it could be replaced with any single digit. So, the interpreter prints out the first three items in the $ sequence, separated by the default delimiter, ,.

answered Jul 8, 2017 at 19:14

answered Jul 8, 2017 at 19:14

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#cQuents, 5 bytes

#3::$

Outputs 1,2,3. This works because of the mode, ::. :: prints the sequence up to n, which in this case is hardcoded in as 3. $ prints the current index - it could be replaced with any single digit. So, the interpreter prints out the first three items in the $ sequence, separated by the default delimiter, ,.