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Timeline for Expand Exponentiation

Current License: CC BY-SA 3.0

9 events
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Feb 20, 2017 at 20:55 history edited fəˈnɛtɪk CC BY-SA 3.0
added 51 characters in body
Feb 20, 2017 at 20:52 comment added Luke If you interpret "The four expressions may be output in any reasonable way as long as they are in order and clearly distinct." to also include returning an array with four different elements, you don't even need the .join()...
Feb 20, 2017 at 18:15 comment added ETHproductions You can save a further byte with .join: a=>b=>[a+'^'+b,(a+'*').repeat(b-1)+a,(a+'+').repeat(Math.pow(a,b-1)-1)+a,1+'+1'.repeat(Math.pow(a,b)-1)].join`=`
Feb 20, 2017 at 14:34 history edited fəˈnɛtɪk CC BY-SA 3.0
added 69 characters in body
Feb 20, 2017 at 8:48 comment added Neil Why not '=1'+'+1'.repeat?
Feb 20, 2017 at 5:52 comment added Yytsi You could use the currying syntax: a=>b=>.
Feb 20, 2017 at 4:06 history edited fəˈnɛtɪk CC BY-SA 3.0
deleted 5 characters in body
Feb 20, 2017 at 3:56 history edited fəˈnɛtɪk CC BY-SA 3.0
added 6 characters in body
Feb 20, 2017 at 3:45 history answered fəˈnɛtɪk CC BY-SA 3.0

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