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Rev

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Don't give me five!

Question :

You will be given the starting and ending integers of a sequence and should return the number of integers within it which do not contain the digit 5. The start and end numbers should be included!

Examples:

1,9 → 1,2,3,4,6,7,8,9 → Result 8

4,17 → 4,6,7,8,9,10,11,12,13,14,16,17 → Result 12

50,60 → 60 → Result 1

-59,-50 → → Result 0

The result may contain five.

The start number will always be smaller than the end number. Both numbers can be also negative!

I'm very curious for your solutions and the way you solve it. Maybe someone of you will find an easy pure mathematics solution.

Edit This is a code-golf challenge, so the shortest code wins.

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\$\begingroup\$ 05AB1E also has vectorized å, which is .å, so you can do Ÿ5.å_O for 6 bytes. \$\endgroup\$

Adnan
– Adnan

2017年01月20日 11:24:12 +00:00
Commented Jan 20, 2017 at 11:24
\$\begingroup\$ negate meaning -n, or n==0?1:0? \$\endgroup\$

ETHproductions
– ETHproductions

2017年01月20日 12:38:05 +00:00
Commented Jan 20, 2017 at 12:38
\$\begingroup\$ @ETHproductions: Sorry, that was unclear. I meant logical negation, so n==0?1:0 \$\endgroup\$

Emigna
– Emigna

2017年01月20日 12:46:47 +00:00
Commented Jan 20, 2017 at 12:46

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