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Changeset 162 for docs


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Timestamp:
Jan 17, 2008, 4:49:34 PM (18 years ago)
Author:
neil.c.c.brown
Message:

Added many notes to the middle of the presentation.

File:
1 edited

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  • docs/trunk/omega-test-slides/omega-test.tex

    r161 r162
    9292\end{array}$
    9393
    94\note{We are checking if any of array indexes can be equal to each other.
    94\note{We are checking if any of array indexes can be equal to each other
    95 within the bounds of the array. So we set the indexes equal in an
    96 equation, and also add inequalities specifying that each index must
    97 be within bounds.
    98
    9599 Note that we must check each possible pairing.
    96100 No solution to any of the equations means the indexes are disjoint, and
    309313\begin{frame}
    310314\fullframegraph{Unsolveable Inequalities}{inequality-unsolveable}
    315(追記) \note{This is an unsolveable pair of inequalities; there is no overlap between the two regions} (追記ここまで)
    311316\end{frame}
    312317
    313318\begin{frame}
    314319\fullframegraph{Inequalities}{inequality-normal}
    320(追記) \note{This is an acceptable pair of inequalities} (追記ここまで)
    315321\end{frame}
    316322
    317323\begin{frame}
    318324\fullframegraph{Redundant Inequalities}{inequality-redundant}
    325(追記) \note{Here, the green inequality is redundant; anything in the red area (追記ここまで)
    326(追記) is also in the green area, so we should only concern ourselves with the (追記ここまで)
    327(追記) red area (and drop the green inequality).} (追記ここまで)
    319328\end{frame}
    320329
    321330\begin{frame}
    322331\fullframegraph{Inequalities $\implies$ Equality}{inequality-equality}
    332(追記) \note{The two equalities begin at the same line but "face" in opposite (追記ここまで)
    333(追記) directions. Therefore the only solutions to the inequality lie on the line. (追記ここまで)
    334(追記) Hence we should just use the line (which is expressable as an equality) (追記ここまで)
    335(追記) and drop the two inequalities. Equalities are easier to deal with than (追記ここまで)
    336(追記) inequalities, so this is a sensible step.} (追記ここまで)
    323337\end{frame}
    324338
    346360
    347361\begin{frame}[fragile]
    348\only<1>{\fullframegraph{Normalising Inequalities}{inequality-tightening-1}}
    349\only<2>{\fullframegraph{Normalising Inequalities}{inequality-tightening-2}}
    362\only<1>{\fullframegraph{Normalising Inequalities}{inequality-tightening-1}
    363\note{The position of this inequality is somewhat wasteful/redundant. We
    364are only interested in integer solutions (here, the crosses on the graph)
    365so the fact that the red region includes a portion of space with no crosses
    366is irrelevant.}}
    367\only<2>{\fullframegraph{Normalising Inequalities}{inequality-tightening-2}
    368\note{We can eliminate this wastefulness by effectively "snap-to-grid". We
    369move the inequality in a direction perpendicular to its line (informally,
    370"towards the red") until it hits the first cross(es). This is now shown
    371on the graph.}}
    350372\only<3>{\fullframegraph{Normalising Inequalities}{inequality-tightening-3}}
    351\only<4>{\fullframegraph{Normalising Inequalities}{inequality-tightening-4}}
    373\only<4>{\fullframegraph{Normalising Inequalities}{inequality-tightening-4}
    374\note{One reason normalisation is useful is illustrated here. In the first
    375of the two pictures, there is an overlap between the two regions so they
    376both seem valid. But in fact there are no integer points in that region.
    377Normalising both equations reveals that the equalities are in fact unsolveable.}}
    352378\end{frame}
    353379
    378404\only<1>{\fullframegraph{Set of Inequalities}{inequality-scalene-1}}
    379405\only<2>{\fullframegraph{Set of Inequalities}{inequality-scalene-2}}
    380\only<3>{\fullframegraph{Set of Inequalities}{inequality-scalene-3}}
    381\end{frame}
    382
    383\begin{frame}[fragile]
    384\only<1>{\fullframegraph{Eliminate $x$}{inequality-scalene-2}}
    406\only<3>{\fullframegraph{Set of Inequalities}{inequality-scalene-3}
    407\note{The preceding three inequalities form a central triangular region.
    408We will now look at how to eliminate the $x$ variable from the equations.}}
    409\end{frame}
    410
    411\begin{frame}[fragile]
    412\only<1>{\fullframegraph{Eliminate $x$}{inequality-scalene-2}
    413\note{In order for a point to be in both the red and green regions,
    414it must be below (i.e. $y$ axis) the point at which they join ($y = 3$).
    415Therefore we can eliminate $x$ here and just use the inequality
    416$y \leq 3$ (see next slide).}}
    385417\only<2>{\fullframegraph{Eliminate $x$}{inequality-scalene-4}}
    386\only<3>{\fullframegraph{Eliminate $x$}{inequality-scalene-5}}
    418\only<3>{\fullframegraph{Eliminate $x$}{inequality-scalene-5}
    419\note{Similarly, in order for a point to be in both the read and
    420blue regions, it must be above ($y$ axis again) the point at which
    421they join ($y=1$). Therefore our new inequality is $y \geq 1$. This
    422inequality is shown on the next slide, and the combination of our
    423two new inequalities is shown on the slide after that.}
    387424\only<4>{\fullframegraph{Eliminate $x$}{inequality-scalene-6}}
    388425\only<5>{\fullframegraph{Eliminate $x$}{inequality-scalene-7}}
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