On 24/06/2014 02:43, Choonster TheMage wrote:
Pretty sure the internal % does n - floor(n/d) * d, which means you can save a division by using the other thing...On 24 Jun 2014 13:52, "Lucas" <cad.lua@lucasjr.nospammail.net> wrote:Ok, my intention was to write such a function function modulus(n, d) return n - (q = math.floor(n/d)) * d, q; end is there any means to write it down just as simple? r, q = modulus(10, 3)Sticking with your existing technique: function modulus(n, d) local q = math.floor(n/d) return n - q * d, q end Using the modulus operator (I'm pretty sure this is correct): function modulus(n, d) return n % d, math.floor(n/d) end
Regards, Choonster