On 12/12/2010 19.57, Geoff Leyland wrote:
t[1] is quicker than #t> 0, especially if t is a long array.
> (Not my idea, Javier Guerra pointed this out in > http://lua-users.org/lists/lua-l/2008-03/msg00540.html) Interesting... I always thought #t required constant time. However, t[1] is not equivalent to #t if the 'array' has a hole in t[1]. -- Enrico