elseifs and the fact that assignmens are not expressions
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- Subject: elseifs and the fact that assignmens are not expressions
- From: Flemming Madsen <lua@...>
- Date: 2007年1月24日 09:17:35 +0100
Hello
I was contemplating a small lua exercise, a program for listing my
currently vim'ed files a'la
local s,e,c,r,line,file,modified,pid,running
local fd = io.popen("sh -c 'vi -r 2>&1'", "r")
while (line = fd:read("*line")) do
^^^^^^
if s,e,c = string.find(line, "^ *file name: ([%w%p]*)") then
^^^^^^^^
file = c
elseif s,e,c = string.find(line, "^ *modified: (%a*)") then
^^^^^^^^
modified = c ~= "no"
elseif s,e,c,r = string.find(line, "^ *process ID: (%d*)(.*)") then
^^^^^^^^^
pid = c
running = string.find(r, "(still running)", 1, true) ~= nil
if file && modified then
io.write(string.format("%d %8d%s %s", modified and 1 or 0,
pid, running and "*" or " ", file)
end
file = nil
running = nil
end
end
fd:close()
Obviously this will not work, since assignments are not expressions in lua,
nor is there any way of embedding assignment in expressions
Is there an easy way around this that i missed. Is this even a candidate
for the FAQ
Best /Flemming*
*