LuaJava and JAXP
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- Subject: LuaJava and JAXP
- From: "Martin Kendall" <martinkendall@...>
- Date: 2004年2月18日 11:20:43 -0000
Hello,
I was very excited to see LuaJava - A very good way to have the power and
beauty of Lua combined with libraries and ubiquity of Java.
I thought I would try a short program to see how it operated:
documentBuilderFactory =
luajava.bindClass("javax.xml.parsers.DocumentBuilderFactory")
factory = documentBuilderFactory:newInstance()
builder = factory:newDocumentBuilder()
document = builder:parse("labels.xml")
root = document:getDocumentElement()
print(root:toString())
This worked beautifully (I'm using Java 1.4.1 on Windows XP) with the file
labels.xml:
<?xml version="1.0" encoding="iso-8859-1"?>
<labels>
<label added="2003年06月20日">
<quote>
<!-- Mixed content -->
<emph>Midwinter Spring</emph> is its own season…
</quote>
<name>Thomas Eliot</name>
<address>
<street>3 Prufrock Lane</street>
<city>Stamford</city>
<state>CT</state>
</address>
</label>
<label added="2003年06月10日">
<name>Ezra Pound</name>
<address>
<street>45 Usura Place</street>
<city>Hailey</city>
<state>ID</state>
</address>
</label>
</labels>
However, when I added the following line to the program:
nodelist = root:getElementsByTagName("label")
I get this error:
xmltest.lua:7: Class luajava.LuaJavaAPI can not access a member of class
org.apache.crimson.tree.ParentNode with modifiers "public"
luajava.LuaException: Error on file xmltest.lua
at luajava.Console.main(Console.java:24)
I would really appreciate it if anyone could tell me what I am doing wrong.
Thanks,
Martin