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We discussed on Saturday whether rejecting parts of dictionary words in passwords would make less secure passwords. We assumed that a word fragment had 3 characters. Chance of password of n characters containing part of a dictionary word: 3 = 42.75% 4 = 67.22% 5 = 81.23% 6 = 89.25% 7 = 93.85% 8 = 96.48% Now vary the size of a word fragment: 1 = 26 100% of search space 2 = 610 90.24% of search space 3 = 7513 42.75% of search space 4 = 46581 10.19% of search space 5 = 124620 1.05% of search space Other stuff: Word count of dictionary: 263,533 words. Size of normal abridged dictionary: about 1/4th of that. Size of average vocabulary (sources vary wildly): 30,000 -- -[Dave Turner Stalk me: (215)-545-2859] ------------------------------------------------------------------------ *** Error: The method "java.lang.Object newInstance();" can throw the checked exception "java/lang/IllegalAccessException", but its invocation is neither enclosed in a try statement that can catch that exception nor in the body of a method or constructor that "throws" that exception. ______________________________________________________________________ Philadelphia Linux Users Group - http://www.phillylinux.org Announcements-http://lists.phillylinux.org/mail/listinfo/plug-announce General Discussion - http://lists.phillylinux.org/mail/listinfo/plug