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unset

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unset -- Unset a given variable

Description

void unset ( mixed var [, mixed var [, ...]])

unset() destroys the specified variables. Note that in PHP 3, unset() will always return TRUE (actually, the integer value 1). In PHP 4, however, unset() is no longer a true function: it is now a statement. As such no value is returned, and attempting to take the value of unset() results in a parse error.

Example 1. unset() example

// destroy a single variable
unset ($foo);
// destroy a single element of an array
unset ($bar['quux']);
// destroy more than one variable
unset ($foo1, $foo2, $foo3);

The behavior of unset() inside of a function can vary depending on what type of variable you are attempting to destroy.

If a globalized variable is unset() inside of a function, only the local variable is destroyed. The variable in the calling environment will retain the same value as before unset() was called.

function destroy_foo() {
 global $foo;
 unset($foo);
}
$foo = 'bar';
destroy_foo();
echo $foo;
The above example would output:
bar

If a variable that is PASSED BY REFERENCE is unset() inside of a function, only the local variable is destroyed. The variable in the calling environment will retain the same value as before unset() was called.

function foo(&$bar) {
 unset($bar);
 $bar = "blah";
}
$bar = 'something';
echo "$bar\n";
foo($bar);
echo "$bar\n";
The above example would output:
something
something

If a static variable is unset() inside of a function, unset() destroyes the variable and all its references.

function foo() {
 static $a;
 $a++;
 echo "$a\n";
 unset($a);
}
foo();
foo();
foo();
The above example would output:
1
2
3

If you would like to unset() a global variable inside of a function, you can use the $GLOBALS array to do so:

function foo() {
 unset($GLOBALS['bar']);
}
$bar = "something";
foo();

Note: unset() is a language construct.

See also isset() and empty().


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