in_array

(PHP 4 >= 4.0.0)

in_array -- Return TRUE if a value exists in an array

Description

bool in_array ( mixed needle, array haystack [, bool strict])

Searches haystack for needle and returns TRUE if it is found in the array, FALSE otherwise.

If the third parameter strict is set to TRUE then the in_array() will also check the types of the needle in the haystack.

Example 1. in_array() example $os = array ("Mac", "NT", "Irix", "Linux"); if (in_array ("Irix", $os)) { print "Got Irix"; } if (in_array ("mac", $os)) { print "Got mac"; } The second condition fails because in_array() is case-sensitive, so the program above will display: Got Irix

Example 2. in_array() with strict example <?php $a = array('1.10', 12.4, 1.13); if (in_array('12.4', $a, TRUE)) echo "'12.4' found with strict check\n"; if (in_array(1.13, $a, TRUE)) echo "1.13 found with strict check\n"; ?> This will display: 1.13 found with strict check

Example 3. in_array() with an array as needle <?php $a = array(array('p', 'h'), array('p', 'r'), 'o'); if (in_array(array ('p', 'h'), $a)) echo "'ph' is found\n"; if (in_array(array ('f', 'i'), $a)) echo "'fi' is not found\n"; if (in_array('o', $a)) echo "'o' is found\n"; ?> // This will output: 'ph' is found 'o' is found

See also array_search().