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5.2. EscapingEscaping is a method of quoting single characters. The escape (\) preceding a character tells the shell to interpret that character literally. Special meanings of certain escaped characters
Note The behavior of \ depends on whether it is itself escaped, quoted, or appearing within command substitution or a here document. # Simple escaping and quoting echo \z # z echo \\z # \z echo '\z' # \z echo '\\z' # \\z echo "\z" # \z echo "\\z" # \z # Command substitution echo `echo \z` # z echo `echo \\z` # z echo `echo \\\z` # \z echo `echo \\\\z` # \z echo `echo \\\\\\z` # \z echo `echo \\\\\\\z` # \\z echo `echo "\z"` # \z echo `echo "\\z"` # \z # Here document cat <<EOF \z EOF # \z cat <<EOF \\z EOF # \z # These examples supplied by St�phane Chazelas. Elements of a string assigned to a variable may be escaped, but the escape character alone may not be assigned to a variable. variable=\ echo "$variable" # Will not work - gives an error message: # test.sh: : command not found # A "naked" escape cannot safely be assigned to a variable. # # What actually happens here is that the "\" escapes the newline and #+ the effect is variable=echo "$variable" #+ invalid variable assignment variable=\ 23skidoo echo "$variable" # 23skidoo # This works, since the second line #+ is a valid variable assignment. variable=\ # \^ escape followed by space echo "$variable" # space variable=\\ echo "$variable" # \ variable=\\\ echo "$variable" # Will not work - gives an error message: # test.sh: \: command not found # # First escape escapes second one, but the third one is left "naked", #+ with same result as first instance, above. variable=\\\\ echo "$variable" # \\ # Second and fourth escapes escaped. # This is o.k. | ||
Escaping a space can prevent word splitting in a command's argument list.
file_list="/bin/cat /bin/gzip /bin/more /usr/bin/less /usr/bin/emacs-20.7" # List of files as argument(s) to a command. # Add two files to the list, and list all. ls -l /usr/X11R6/bin/xsetroot /sbin/dump $file_list echo "-------------------------------------------------------------------------" # What happens if we escape a couple of spaces? ls -l /usr/X11R6/bin/xsetroot\ /sbin/dump\ $file_list # Error: the first three files concatenated into a single argument to 'ls -l' # because the two escaped spaces prevent argument (word) splitting.
The escape also provides a means of writing a multi-line command. Normally, each separate line constitutes a different command, but an escape at the end of a line escapes the newline character, and the command sequence continues on to the next line.
(cd /source/directory && tar cf - . ) | \ (cd /dest/directory && tar xpvf -) # Repeating Alan Cox's directory tree copy command, # but split into two lines for increased legibility. # As an alternative: tar cf - -C /source/directory . | tar xpvf - -C /dest/directory # See note below. # (Thanks, St�phane Chazelas.)
If a script line ends with a |, a pipe character, then a \, an escape, is not strictly necessary. It is, however, good programming practice to always escape the end of a line of code that continues to the following line.
echo "foo bar" #foo #bar echo echo 'foo bar' # No difference yet. #foo #bar echo echo foo\ bar # Newline escaped. #foobar echo echo "foo\ bar" # Same here, as \ still interpreted as escape within weak quotes. #foobar echo echo 'foo\ bar' # Escape character \ taken literally because of strong quoting. #foo\ #bar # Examples suggested by St�phane Chazelas.