Java Utililty Methods Integer to Binary

String int2binString(int x)
intbin String

String s = "";
for (int ii = 0; ii < 32; ii++) {
 if ((ii > 0) && (ii % 4 == 0)) {
 s = " " + s;
 s = hex_digit[(x & (1 << ii)) >>> ii] + s;
return s;
...

String integerToBin(int value)
integer To Bin

return Long.toBinaryString(0x0000000100000000L | ((value) & 0x00000000FFFFFFFFL)).substring(1);

String integerToBinaryString(int value)
integer To Binary String

return (value < 0 ? "1" : "0") + Integer.toBinaryString(Math.abs(value));

String integerToBinaryString(int value, int numberOfBits)
Converts a value from a normal integer to a binary value of type String.

StringBuilder stringBuilder = new StringBuilder();
stringBuilder.append(Integer.toBinaryString(value));
while (stringBuilder.length() != numberOfBits) {
 String old = stringBuilder.toString();
 stringBuilder = new StringBuilder();
 stringBuilder.append("0" + old);
String finalizedBinaryValue = stringBuilder.toString();
...

String integerToBinString(final int aValue, final int aFieldWidth)
converts an integer to a bin string with leading zeros

final long mask = (long) (Math.pow(2.0, aFieldWidth) - 1L);
StringBuilder sb = new StringBuilder(Long.toBinaryString(aValue & mask));
int numberOfLeadingZeros = Math.max(0, aFieldWidth - sb.length());
for (; numberOfLeadingZeros > 0; numberOfLeadingZeros--) {
 sb.insert(0, '0');
return sb.toString();

String intToBinary(int binary, int digits)
Converts the given integer to a String representing a binary number with the specified number of digits For example when using 4 digits the binary 1 is 0001

String temp = Integer.toBinaryString(binary);
int foundDigits = temp.length();
String returner = temp;
for (int i = foundDigits; i < digits; i++) {
 returner = "0" + returner;
return returner;

char[] intToBinary(int i)
int To Binary

char[] values = new char[32];
for (int pos = 31; pos >= 0; pos--, i >>= 1) {
 if ((i & (int) 0x01) == (int) 1)
 values[pos] = '1';
 else
 values[pos] = '0';
return values;
...

String intToBinary(int i, int byteLength)
int To Binary

String binString = Integer.toBinaryString(i);
while (binString.length() < byteLength * 8) {
 binString = "0" + binString;
return binString;

String intToBinary(long value, int bits)
This method converts int values to binary-string.

char[] returnValue = new char[bits];
boolean wasNegative = false;
if (value < 0) {
 wasNegative = true;
 ++value;
 value = (value * -1);
for (int i = 0; i < bits; ++i) {
...

String intToBinString(int val, int width)
int To Bin String

String str = Integer.toBinaryString(val);
if (str.length() >= width) {
 return str;
return mZeroes.substring(0, width - str.length()) + str;